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The vector magnitude and direction or the components of the vector.
THE MAGNITUDE OF ELECTRIC FIELD IS kq/radius-square . IF THE Q[THAT IS CHARGE ] IS BIGGER IN MAGNITUDE OR IF THE DISTANCE BETWEEN THE CHARGE PARTICLE AND POINT CHARGE IS MINIMUM THAN WE CAN SAY THAT IT IS A STRONG ELECTRIC FIELD
The fact that both a magnitude (number) and a direction is required to specify it.
In a vector quantity, it is important to specify a direction. In a scalar quantity, it isn't. Vectors (such as force) have a magnitude (size) and a direction (such as North). Scalars have only a magnitude.
Velocity is a vector; to specify velocity, you indicate a speed (a magnitude), and a direction. If two objects move in different directions, their velocities will be different, even if their speeds are the same.Velocity is a vector; to specify velocity, you indicate a speed (a magnitude), and a direction. If two objects move in different directions, their velocities will be different, even if their speeds are the same.Velocity is a vector; to specify velocity, you indicate a speed (a magnitude), and a direction. If two objects move in different directions, their velocities will be different, even if their speeds are the same.Velocity is a vector; to specify velocity, you indicate a speed (a magnitude), and a direction. If two objects move in different directions, their velocities will be different, even if their speeds are the same.
A large "test charge" would influence the field you want to measure.
The vector magnitude and direction or the components of the vector.
A scalar is a magnitude that doesn't specify a direction. A vector is a magnitude where the direction is important and is specified.
You cannot ask for an absolute magnitude and specify the distance, as the absolute magnitude is derived from a set distance of 32.616 light years.At that distance, the absolute magnitude of the Sun is +4.83From Earth the apparent magnitude -26.74
convention, it could have been either way but they had to pick one so everyone got same answer.
linear units only give the magnitude of a operand, they do not specify the direction
The fact that both a magnitude (number) and a direction is required to specify it.
THE MAGNITUDE OF ELECTRIC FIELD IS kq/radius-square . IF THE Q[THAT IS CHARGE ] IS BIGGER IN MAGNITUDE OR IF THE DISTANCE BETWEEN THE CHARGE PARTICLE AND POINT CHARGE IS MINIMUM THAN WE CAN SAY THAT IT IS A STRONG ELECTRIC FIELD
By defining priorities in the MX record.
To specify a vector, you need a length (or magnitude), and a direction.
You need to specify which camp.
yes