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No, because the chart shows reduction potentials. Ered cathode - Ered anode = emf just requires you to plug in the reduction potentials the way they are. A common equation is Ered cathode + Eox anode = emf, in which case you would have to flip the sign of the anode's reduction potential, since you would need its oxidation potential. But the equation Ered cathode - Ered anode = emf is simpler and probably formed to be that way.

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Q: When finding the emf of a redox reaction by Ered cathode - Ered anode and a half-reaction is reversed on the chart do you flip the sign of its reduction potential?
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