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Capacitors may be connected in series to provide a capacitance with an effective working voltage higher than that of any of the individual units, (but the effective capacitance is less than that of any individual.) Capacitors may be connected in parallel to provide an effective capacitance value greater than that of any of the individual units, (but working voltage is equal to the lowest among the individuals).
No. If you connect in series, positive to negative and then connect load to the remaining positive and negative terminals then the voltage at these terminals is the added voltage of the batteries thus connected, but the capacity (amphours) stays the same.
2-3Figure 2-1B.-Interelectrode capacitance in a vacuum tube. 100 MEGAHERTZ.Figure 2-1C.-Interelectrode capacitance in a vacuum tube. INTERELECTRODE CAPACITANCE IN ATUNED-PLATE TUNED-GRID OSCILLATOR.A good point to remember is that the higher the frequency, or the larger the interelectrodecapacitance, the higher will be the current through this capacitance. The circuit in figure 2-1C, shows theinterelectrode capacitance between the grid and the cathode (Cgk) in parallel with the signal source. Asthe frequency of the input signal increases, the effective grid-to-cathode impedance of the tube decreasesbecause of a decrease in the reactance of the interelectrode capacitance. If the signal frequency is 100megahertz or greater, the reactance of the grid-to-cathode capacitance is so small that much of the signalis short-circuited within the tube. Since the interelectrode capacitances are effectively in parallel with thetuned circuits, as shown in figures 2-1A, B, and C, they will also affect the frequency at which the tunedcircuits resonate.Another frequency-limiting factor is the LEAD INDUCTANCE of the tube elements. Since the leadinductances within a tube are effectively in parallel with the interelectrode capacitance, the net effect is toraise the frequency limit. However, the inductance of the cathode lead is common to both the grid andplate circuits. This provides a path for degenerative feedback which reduces overall circuit efficiency.
Current travels in loops. In series you have one loop, or path for current to take. With parallel connections, there's at least two. This is why current divides in parallel and not in series.The usual problem here is to find the equivalent resistance, or capacitance. In the following formulae, R is the value of the equivalent resistance, while R1, R2, and R3 are the values of the...It can be used in the connection of emf..to have the greater current that we desired.so that it can produced a current.Capacitors may be connected in series to provide a capacitance with an effective working voltage higher than that of any of the individual units, (but the effective capacitance is less than that of... CommentTo answer the question... it was probably Count Alessandro Volta (1745 - 1827), an Italian physicist, credited with inventing the chemical battery.
Ideal capacitors and ideal inductors do not dissipate energy, they store energy and release energy like a spring or pendulum. This type of impedance is called reactance as opposed to resistance. Reactance is represented by imaginary numbers, while resistance is represented by real numbers. Real world capacitors have an Effective Series Resistance (ESR) that consumes a small, usually negligible, amount of energy.
c =c1 +c2
A: the capacitance will increase. in series it will decrease accordingly CPARALLEL = Summation1-N (CN) CSERIES = 1 / Summation1-N (1 / CN)
Capacitors may be connected in series to provide a capacitance with an effective working voltage higher than that of any of the individual units, (but the effective capacitance is less than that of any individual.) Capacitors may be connected in parallel to provide an effective capacitance value greater than that of any of the individual units, (but working voltage is equal to the lowest among the individuals).
It looks like all three of your capacitors have the same value. So the effective capacitance when they're all conected in series is 1/3 of that value = 0.005 fd.
As far as potential difference is concerned if they are in series we have to add them. If they are in parallel the potential difference remains the same. So we need two parallel sets to be connected in series. Now as we connect in parallel the effective capacitance would be got by adding the capacitance. If capacitors of equal value are connected in series, then its value will be reduced to half of the individual. So let us construct two in parallel. So effective will be 4 uF but with 10 V Another set of two in parallel has 4 uF with 10 V. Now these two sets are connected in series. Hence the effective would become 2 uF but the voltage will be 10+10 ie 20 V. Hence the problem is solved. So we need two sets in series
A Colpitts oscillator is the electrical dual of a Hartley oscillator. In the Colpitts circuit, two capacitors and one inductor determine the frequency of oscillation. The feedback needed for oscillation is taken from a voltage divider made by the two capacitors, where in the Hartley circuit the feedback is taken from a voltage divider made by two inductors (or a tapped single inductor). (Note: the capacitor can be a variable device by using a varactor). Oscillation frequency The ideal frequency of oscillation for the circuit is given by the equation: where the series combination of C1 and C2 creates the effective capacitance of the LC tank. Real circuits will oscillate at a slightly lower frequency due to junction capacitances of the transistor and possibly other stray capacitances
Often, I need a capacitor of a certain value for a project I am building and I do nothave one. I find myself in this awkward situation on almost every rainy day. Ratherthan going out in the rain to get one, I can combine two capacitors that I do have,to yield the capacitance value that I need. I have the choice to combine them inseries or in parallel.-- When I configure therm in parallel, their combined effective capacitance is(the sum of their individual values).-- When I configure them in series, their combined effective capacitance is(the product of their individual values)/(the sum of their individual values)I typically choose series, just to make the math harder and give myself the practice.
No. If you connect in series, positive to negative and then connect load to the remaining positive and negative terminals then the voltage at these terminals is the added voltage of the batteries thus connected, but the capacity (amphours) stays the same.
the method can't be used in that case... not that effective
No unless it a large industrial one, and if you could it would not be cost effective
Practically, there are some factors that affect the frequency stability of Variation in temperature Oscillator • Circuit Components - Values of R, L and C changes with temperature • Transistor Parameters - causes variation in transistor parameters • Supply Voltages - Variations in power supply • Stray Capacitances • Output Load - Variations of load causes a change in effective resistance • Inter‐element Capacitance
2-3Figure 2-1B.-Interelectrode capacitance in a vacuum tube. 100 MEGAHERTZ.Figure 2-1C.-Interelectrode capacitance in a vacuum tube. INTERELECTRODE CAPACITANCE IN ATUNED-PLATE TUNED-GRID OSCILLATOR.A good point to remember is that the higher the frequency, or the larger the interelectrodecapacitance, the higher will be the current through this capacitance. The circuit in figure 2-1C, shows theinterelectrode capacitance between the grid and the cathode (Cgk) in parallel with the signal source. Asthe frequency of the input signal increases, the effective grid-to-cathode impedance of the tube decreasesbecause of a decrease in the reactance of the interelectrode capacitance. If the signal frequency is 100megahertz or greater, the reactance of the grid-to-cathode capacitance is so small that much of the signalis short-circuited within the tube. Since the interelectrode capacitances are effectively in parallel with thetuned circuits, as shown in figures 2-1A, B, and C, they will also affect the frequency at which the tunedcircuits resonate.Another frequency-limiting factor is the LEAD INDUCTANCE of the tube elements. Since the leadinductances within a tube are effectively in parallel with the interelectrode capacitance, the net effect is toraise the frequency limit. However, the inductance of the cathode lead is common to both the grid andplate circuits. This provides a path for degenerative feedback which reduces overall circuit efficiency.