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Yes, when passing an argument by reference, changes to the argument made within the module will directly affect the original variable in the calling part of the program. This is because the reference to the original variable's memory address is passed to the module, allowing it to modify the variable directly.

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Q: When passing an argument by reference the module can modify the argument in the calling part of the program?
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Related questions

When the module can modify the argument in the calling part of the program?

when it is passed by reference


What happen when a c program passes an array as a function argument?

When an array name is passed as a function argument, the address of the first element is passed to the function. In a way, this is implicit call by reference. The receiving function can treat that address as a pointer, or as an array name, and it can manipulate the actual calling argument if desired.


When argument are passed by value the function works with the original arguments in the calling program?

When a function is passed by value the calling function makes a copy of the passed argument and works on that copy. And that's the reason that any changes made in the argument value does gets reflected to the caller.


What is calling by reference how it is different from call by value in c program?

Calling a function by value means the variable will be copied. That means that, any changes you make to the variable will be applied to the copy, and not the real one. If you pass by reference, the actual intended variable is modified.


Simple c program for the call by reference?

In call by reference, you are calling the program by passing the variables address(reference) to it. This is done through the use of functions. Any changes made in the variables to the function will be reflected even the calling function.Here is a code snippet for swapping two numbers.#includevoid swap( int *a, int *b){int temp = *a;*a = *b;*b = temp;}int main(){int a=8, b=9;printf("The value of a and b before swap = %d %d\n", a, b);swap(a,b);printf("The value of a and b after swap = %d %d\n", a, b);return 0;}


What does call-by-Value and call-by-Reference mean?

When we swap values in function, that time "Call by value" swaps copied value not the exact values. so it doesn't reflect on main function. But in case of "Call by reference", we swap actual value which is available at that reference or address.


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Application.


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Command line argument is a value that is passed to a program whenever the program is executed. It is used to avoid hard coding.


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