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Q: When the distance between two charges is halved the electrical force between them?
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When the distance between two charges is halved the electric force between the charges?

The forces in each direction are quadrupled.


Determine the amount by which the electric force between two charges is increased when the distance between the charges is halved?

If the charge on the object is double than the force between them is double


Two point charges q1 and q2 are located a distance r apart in a vacuum Which change to the charges will halve the magnitude of the electric charge between them?

Hello, some error in the words. Electric "force" not electric charge. A/s we increase the distance between the charges ./2 times then force between them will be halved.


If distance between earth and sun is halved how many days constitute a year?

1/8 of a yr


What will happen to the gravitational force when the distance between the centers of the two bodies is halved?

The force will increase fourfold.


How does the gravitional force change if theier mass are halved?

If the masses of two objects are each halved, and the distance between them doesn't change, then the mutual gravitational forces of attraction between them are reduced to 1/4 of their original magnitude.


When the masses are doubled and separation is halved what effect do they have on the gravitational force between the masses?

The effect of dubling the massesa and halving the distance is to increase the gravitational force by a factor of 16.


How would the force of gravity between two masses be affected if the separation distance between them were halved?

The gravitational force will become 4 times..


What happens to the electric force when two objects are separated by 1 meter and each has a positive charge when the distance between the objects is halved?

The electric force becomes four times stronger.


Determine the amount by which the electric force between two charges is increased when the distance between the charge is halved?

E=kq/r^2 So, when the distance id doubled, the change is taken down by a factor of 1/4. In other words, if the distance was 3, and then 6, this is what would happen: E=kq/(3)^2=kq/9 and then when r = 6, E=kq(6)^2=kq/36=kq/9*1/4 Thus, reduced by a factor of four or multiplied by 1/4


What is 8000 halved and halved again?

2,000


What happen gravitation force of attraction between two object if mass of one of the object is halved?

The one with the larger mass would pull the halved mass one toward it