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E=kq/r^2

So, when the distance id doubled, the change is taken down by a factor of 1/4.

In other words, if the distance was 3, and then 6, this is what would happen:

E=kq/(3)^2=kq/9

and then when r = 6,

E=kq(6)^2=kq/36=kq/9*1/4

Thus, reduced by a factor of four or multiplied by 1/4

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