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Determine the amount by which the electric force between two charges is increased-when the distance between charges is halved?
If the distance between two charges is halved, the electric force between them is increased by a factor of 4. This is because the electric force is inversely proportional to the square of the distance between the charges according to Coulomb's Law. So, decreasing the distance by half means the force increases by a factor of (1/0.5)^2 = 4.
How does the electric force between two charged particles change if the distance between them is increased by a factor of 2?
The electric force between two charged particles decreases by a factor of 4 when the distance between them is increased by a factor of 2. The electric force is inversely proportional to the square of the distance between the charged particles.
What are two ways the electric force between two charged objects can be increased?
The electric force between two charged objects can be increased by increasing the magnitude of the charges on the objects or by decreasing the distance between the objects.
How can one determine the electric field between two plates?
To determine the electric field between two plates, one can use the formula E V/d, where E is the electric field, V is the voltage difference between the plates, and d is the distance between the plates. This formula relates the electric field to the voltage and distance, allowing for the calculation of the electric field strength.
How does the electric force between two charged particles change if the distance between them is increased by a factor of two?
The electric force between two charged particles is inversely proportional to the square distance between them.Accordingly, it is reduced by a factor of 9
What two factors determine the amount of electric force between two objects?
The amount of electric force between two objects is determined by the magnitude of the charges on the objects and the distance between them. The force increases with the magnitude of the charges and decreases with the square of the distance separating the objects.
Determine the amount by which the electric force between two charges is increased when the distance between the charge is halved?
E=kq/r^2 So, when the distance id doubled, the change is taken down by a factor of 1/4. In other words, if the distance was 3, and then 6, this is what would happen: E=kq/(3)^2=kq/9 and then when r = 6, E=kq(6)^2=kq/36=kq/9*1/4 Thus, reduced by a factor of four or multiplied by 1/4
If you double the distance between two objects the electric force is .?
If you double the distance between two objects, the electric force between them decreases by a factor of four. This is because electric force is inversely proportional to the square of the distance between the charges.
How does distance affect the electric force according to Coulomb and law?
According to Coulomb's law, the electric force between two charged objects is inversely proportional to the square of the distance between them. This means that as the distance between the objects increases, the electric force between them decreases. Conversely, as the distance decreases, the electric force increases.
What are two things that decide on how powerful an electric force is?
The two main factors that determine the strength of an electric force between two charged objects are the magnitude of the charges involved and the distance between the charges. The greater the charges and the closer the objects are, the stronger the electric force will be.
What happens to the electric force if you double the distance between two objects?
The electric force between two objects decreases to one-fourth of the original force if the distance between them is doubled. This is because the electric force is inversely proportional to the square of the distance between the charges.
What happens to the force between charged and uncharged objects as the distance between them increased?
as the distance is increased statically induced charge in the uncharged object reduced to a minimum. Thus coulombic force which is directly proportional to the product of the charges tends to 0.
