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Using the formula H=mS(t2-t1) we get H=0.6 x 1x 10=6 KJ of heat. Here H is heat, m is mass of substance, S is specific heat capacity of substance, t2 final temperature and t1 is initial temp.
4.5181 atm P1/T1 = P2/T2 where T = temp in Kelvin
V1/T1 = V2/T2 Where temperature must be in Kelvins 67C + 273 = 340 K So 140/340 = 50/T2 Find T2 340/140(50) = T2 T2 = 121 K or -152C
Multiple areas of T2 spots were seen in the white matter on both sides
Bacteriophage
The SHLD (Store H&L Direct) instruction takes 5 machine cycles and 16 clock states, not including any wait states. Opcode fetch: T1, T2, T3, and TX Low order address fetch: T1, T2, T3 High order address fetch: T1, T2, T3 Store L: T1, T2, T3 Store H: T1, T2, T3
For energy problems like this the following equation is used: E = m*c*(T2-T1) where E is the energy amount added m is the mass of the thing being heated c is the specific heat of the object being heated T2 is the temperature after the heat T1 is the temperature before the heat is added. If you're not familiar c, the specific heat of a substance is a property which is a measure of how much heat is required to heat 1 gram of the substance by 1 degree Celsius. For water it is 1.0 cal/g/C. Since there are 4.186J per calorie you could also use c=4.186 J/g/C. You can rearrange the above equation to solve for T2: T2 = T1 + E/(m*c) = 10C + (420J)/((35g)*(4.186J/g/C)) = 13 C I hope this helps
V1/T1 = V2/T2 T1 = 278K, T2 = 333K75 ml/278K = V2/333KV2 = (75/278K)*(333K)V2 = 89.8 ml
Using the formula H=mS(t2-t1) we get H=0.6 x 1x 10=6 KJ of heat. Here H is heat, m is mass of substance, S is specific heat capacity of substance, t2 final temperature and t1 is initial temp.
Use the equation m1c1(Tf-T1)= - m2c2(Tf-T2) you get 46.6 C
Type your answer here... it is a T2 hyperintense foci
4.5181 atm P1/T1 = P2/T2 where T = temp in Kelvin
V1/T1 = V2/T2 Where temperature must be in Kelvins 67C + 273 = 340 K So 140/340 = 50/T2 Find T2 340/140(50) = T2 T2 = 121 K or -152C
Air
If you start on the G on the second line on the staff and then go to the G above the staff, the fingerings go like this: 0-T12-T2-T0-T12-T2-T2-T0-T2-T2-T12-T0-T2-T12-0 (G, A, B, C, D, E, F#, G, F#, E, D, C, B, A, G)
win the stick t2 tournament, as strange as that may seem
T2 = P2 x T1 / P1