When copper carbonate is heated, Cu(CO3) forms Copper Oxide CuO and CO2. When Co2 is passed through lime water, it reacts with the calcium in the solution to form the precipitate, calcium carbonate Ca(CO3) which makes the water "milky".
CuCO3(s)-----heat---->CuO(s)+CO2(g) black
CuCO3 + Heat --> CuO + O2 Green Copper Carbonate when heated will form Copper Oxide and Oxygen
Water has.
sodium oxide, carbon dioxide and water 2nd answer: there will be no effect on sodium carbonate if it is heated as sodium carbonate will not be decompose upon heating.
Because it is easier. The molecular formula of copper carbonate is CuCO3. When it decomposes it loses a CO2 molecule. If it became Copper 1 oxide(Cu2O then it would have to combine with another molecule(releasing O). Instead it becames copper2 oxide(CuO) because that is an easier transition.
Because it undergoes thermal decomposition. If you give heat to Copper (II) carbonate, it will decompose to form Copper (II) oxide. Instead of saying green copper carbonate, I guess it is safer and better to say copper (II) carbonate.
CuCO3(s)-----heat---->CuO(s)+CO2(g) black
CuCO3 + Heat --> CuO + O2 Green Copper Carbonate when heated will form Copper Oxide and Oxygen
Heating copper carbonate (CuCO3) should result in the generation of copper oxide (CuO) and carbon dioxide gas (CO2). Therefore, the weight (mass) of the material remaining should decrease by an amount equal to the mass of CO2 lost. If the mass didn't change, you didn't heat the copper carbonate sufficiently to cause the decomposition.
keep heat in copper is a good heat conductor.
Water has.
This means that copper will not absorb the heat from the water as much as the aluminum. Aluminum will "steal" more heat from the water- which you do not want. You need the heat to stay with the water until it serves its purpose.
Endothermic because thermal decomposition is the breakdown of a compound using heat. Remember endo means more energy is taken in breaking the bonds of copper carbonate than there is given out when making the bonds of copper oxide and carbon dioxide.
Heat it
sodium oxide, carbon dioxide and water 2nd answer: there will be no effect on sodium carbonate if it is heated as sodium carbonate will not be decompose upon heating.
Copper Oxide (CuO) + Water (H(sub2)O)
You need to know the specific heat for copper. Then use q = mc∆T for copper and water. Heat lost by the copper MUST equal heat gained by the water. You can then solve for T2 of the water.