Want this question answered?
Carefully arrange 12 rows with 8 coins in each row.
by 2 rows
90000
13 rows of 7 7 rows of 13
Yes, each would have 14, as 14 x 4 = 56.
You can't arrange 12 apples into 5 rows with four in each. To do that you would need 20 apples because 5 rows of 4 = 20 or 5x4=20. You can arrange 12 apples into 3 groups of 4 because 3x4=12
8
You can have: 1 row of 36 2 rows of 18 3 rows of 12 4 rows of 9 or 6 rows of 6, so in total there are 5 ways.
You could try 1 row of 91 or 7 rows of 13.
You cannot. Two rows and one column are good for only two numbers.
The horizontal rows are called periods, there are 7. The vertical rows are groups and there are 18.
They can be called banded rows.