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To find the amount in moles of 3.80g of zinc (Zn), you need to divide the mass by the molar mass of Zn, which is approximately 65.38 g/mol. 3.80g Zn / 65.38 g/mol ≈ 0.058 moles Zn
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To find the oxidation number of zinc (Zn) in zinc nitrate (Zn(NO3)2), you start by recognizing that nitrate (NO3) has a charge of -1. Since there are two nitrate ions in the compound, the total negative charge is -2. To balance this, the oxidation number of zinc must be +2. Therefore, the oxidation number of Zn in Zn(NO3)2 is +2.
To find the number of moles in 3.80 g of Zn, you first need to calculate the molar mass of Zn, which is 65.38 g/mol. Then, divide the mass given (3.80 g) by the molar mass to get the number of moles, which is approximately 0.058 moles of Zn.
The answer is: Zn www.webelements.com Hope this helps. The answer is: Zn www.webelements.com Hope this helps.
Calculated by dividing mass (in grams) by atomic mass of Zn: 3.45(g) / 65.38(g/mole) = 0.0528 mole
Zn:*Zn *for more info: http://www.chemicalaid.com/element.php?symbol=Zn
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Zn + CuSO4 --> ZnSO4 + Cu 1.75g CuSO4 * (1moleCuSO4/159.62gCuSO4) * (1moleZn/1moleCuSO4) * (65.38gZn/1moleZn) = .7168g Zn 2.00g Zn - .7168g Zn = 1.2832g Zn in Excess