CuCl2(s) = Cu^2_(aq) + + 2Cl^-(aq)
In solution the chloride anions )Cl^-) are colourless ; see also dissolved common salt (NaCl)
So it must be the copper cations (Cu^2+) that gives the colour blue.
20.2 g of CuCl2 = .1502 mol CuCl2 M=mol/L M=.1502 mol/L
Copper is corroded in a sodium chloride solution; CuCl2 is formed.
CuCl2 is the product.
Copper is dissolved:2 FeCl3 + Cu = 2 FeCl2 + CuCl2
NiCl2 + 2Na --> 2NaCl + Ni
CuCl2 does NOT burn per se. However, when CuCl2 is dissovled in water in to Cu^2+ ions and Cl^- ions. Pass a ni-chrome or platinum wire through the solution, and then pass the wire through a Bunsen Burner flame. The flame colour will becomes a beautiful Blue/Green colour.
Under normal conditions CuCl2 can exist in either a solid state or in aqueous solution.
Cu(CO3) + 2HCl --> CuCl2 + H2O + CO2 CuCl2 product, when dry is a yellow/brown powder. However, when wet it forms a co-ordination complex with the water in the solution: CuCl2.2H2O --> Cu(Cl)2(H2O)2 The electronic structure of transition metals and ligands cause visible colours. In this case the solution is blue/green in colour. If you dry the solution down you will get a blue/green powder. Drying further in a dessicator will give the yellow/brown anhydrous CuCl2.
20.2 g of CuCl2 = .1502 mol CuCl2 M=mol/L M=.1502 mol/L
Copper is corroded in a sodium chloride solution; CuCl2 is formed.
The chemical equation for the reaction that occurs when zinc metal is added to a solution of copper II chloride is: Zn + CuCl2 -> Cu + ZnCl2.
CuO + 2 HCl -> CuCl2 + H2O Please see the link.
First multiply .131ml and 7.95M to get the moles of Cucl2. (You will need this later) Then find the moles per 49.5ml diluted solution. (6.1g divided my molar mass) Then set both equal to each other Original mol/X = Diluted mol/49.5ml and solve for X This should work
Copper carbonate powder is a bluish green. When colorless sulphuric acid is added, the resulting solution has a slightly diluted color and a bunch of bubbles appear, making the color a lighter bluish green. However, when this solution is introduced to a flame (which would ordinarily be yellow), the flame burns green.
K[CuCl2]
Copper is dissolved:2 FeCl3 + Cu = 2 FeCl2 + CuCl2
CuCl2 is the product.