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What is the molarity of a solution prepared by dissolving 20.00g CaCl2 in enough water to make 1.00L of solution?
Wiki User
∙ 8y ago
20.2 g of CuCl2 = .1502 mol CuCl2
M=mol/L
M=.1502 mol/L
Wiki User
∙ 15y ago
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Calculate the molarity of a solution of glycerol made by dissolving 43.000 mL glycerol at 15 degrees C in enough water to make 200.00 mL of solution?
2.89
A solution is made by dissolving 19.52 g of SnF2 into enough water to make 770 mL of solution What is the molarity of the solution?
the molarity is found by: 19.52g/770mL x 1 mole/156.7g x 1000mL/1L=0.618 mole i got 156.7g by using the chemical makeup of the solution SnF2: Sn's atomic number being 118.7 and rounding F's atomic number to 19.
How do you determine the molarity of a solution containing 18.2g C6H12O6and enough water to reach 6.3L?
Moles of solute ---------------- Liters of solution So, convert your grams to moles by dividing by the molar mass (add together the atomic masses of the solution) and then that will give you your moles. Divide that number by your 6.3 Liters. That number is your molarity.
2.431 g of h2c2o4 x 2h2o was obtained and dissolved in enough dI water to form 250.0 ml of solution what is the concentration of the resulting of h2c2o4 solution?
Molarity (concentration ) = moles of solute/Liters of solution 250.0 ml = 0.250 liters 2.431 grams H2C2O4 * 2H2O ( 1mole cpd/ 126.068 grams) = 0.01928 moles H2C2O4 * 2H2O Molarity = 0.01928 moles cpd/0.250 liters = 0.07712 Molarity
What is the molarity of a solution prepared by dissolving 7 grams of NaCL in enough water to make a 450.0 mL solution?
Molarity = moles solute/liter solutionmoles solute = 7 g NaCl x 1 mol NaCl/58 g NaCl = 0.12 moles NaClliters of solution = 450.0 ml x 1 L/1000 ml = 0.450 litersmolarity = 0.12 moles/0.450 liters = 0.268 M = 0.3 M (one sig fig)
What is the molarity of a solution made by dissolving 23.4g of sodium sulphate in enough water to make up a 125ml solution?
The molarity of a solution made by dissolving 23,4 g of sodium sulphate in enough water to make up a 125 mL solution is 1,318.
What is the molarity of a solution made by dissolving 3.09 moles of Nacl in 1.50 L of solution?
what is the molarity of a solution prepared by dissolving 36.0g of NaOH in enough water to make 1.50 liter of solution?
What is the molarity of a solution prepared by dissolving 1.56 grams of gaseous HCl in enough water to make 26.8 mL of solution?
Find moles of HCl first. 1.56 grams HCl (1mole HCl/36.458 grams) = 0.0428 moles HCl Molarity = moles of solute/volume of solution Molarity = 0.0428 moles/26.8 ml = 0.00160 milli-Molarity, or more to the point; = 1.60 X 10^-6 Molarity of HCl
Calculate the molarity of a solution of glycerol made by dissolving 43.000 mL glycerol at 15 degrees C in enough water to make 200.00 mL of solution?
2.89
An alcoholic iodine solution is prepared by dissolving 4.65 g of iodine crystals in enough alcohol to make a volume of 235 mL Calculate the molarity of iodine in the solution?
molarity = no. of moles of solute/liter of solution no. of moles of I2 = mass in grams/molar mass = 4.65/253.81 = 0.01832 mol M = 0.01832 mol/0.235 L = 0.0780 mol/L
A solution is made by dissolving 19.52 g of SnF2 into enough water to make 770 mL of solution What is the molarity of the solution?
the molarity is found by: 19.52g/770mL x 1 mole/156.7g x 1000mL/1L=0.618 mole i got 156.7g by using the chemical makeup of the solution SnF2: Sn's atomic number being 118.7 and rounding F's atomic number to 19.
Solution is prepared by dissolving 13.3g ammonium sulfate in enough water to make 100.0 mL of stock solution A 12.00 mL sample of this stock solution is added 57.00 mL of water Calculate the concen?
sdfa
What is the molarity of sodium sulphate in a solution prepared by dissolving 15.5g in enough water to make 35ml of solution?
Molarity = moles of solute/volume of solution Find moles NaCl 55 grams NaCl (1mol NaCl/58.44 grams) = 0.941 moles NaCl Molarity = 0.941 moles NaCl/35 Liters = 0.027 Molarity NaCl ( sounds reasonable as 55 grams is not much in 35 Liters of water, which would be about 17.5 2 liter sodas )
What is the molarity of a solution made by dissolving 58.44 g of NaCl in enough water to make 1.0 L of solution?
Divide grams (mass) by molar mass to find moles58.44 (g NaCl/L) / [22.99+35.45](g NaCl/mol NaCl)= 1.000 mol/L NaCl
What is the molarity of 20.2 g of potassium nitrate in enough water to make 250.0 mL of solution?
0.8M
What is the molarity of a solution formed by mixing 20.0 g sulfuric acid with enough water to make 500.0 mL of solution?
0.408 M
What is the concentration of FeCl3 in a solution prepared by dissolving 40.0 g of FeCl3 in enough water to make 275 mL of solution?
Look up or calculate the molecular weight/molar mass of FeCl3. Then... 40.0 g FeCl3/MW FeCl3/0.275 L = M (concentration of FeCl3 in solution)
