If the ball's motion is in the horizontal direction, not far at all. So, let's assume you mean the ball's motion is entirely in the vertical direction, and the 50 joules represents the kinetic energy of the ball. If the 50 joules is all kinetic and the ball is heading upward, it will reach its highest point when its kinetic energy is zero and its potential energy due to gravity is at its greatest. At that point all the kinetic energy will have been turned into potential energy, so when the ball is at its apex, its potential energy will be 50 joules. The formula is pretty simple: Ep = mgh. In English, the potential energy, Ep, is the product of the mass, the acceleration due to gravity, and height. So, 50 = 2 * 9.8 * h. Solving for h gives you h = 2.55 meters.
E=1/2mv**2
vf**2=vi**2+2ad
m=2kg
a=9.81m/s**2
vf**2=0 (apex of throw the ball is stationary)
E=1/2mv**2
2E=mv**2
2E/m=v**2
0=2E/m+2ad
-2E/m = 2ad
-E/m = ad
-E/(ma) = d
At maximum height, KE=0 because all energy is potential energy
Kinetic energy is dependent on which point you are talking about. When it is about to be dropped, kinetic energy is zero. When it reaches almost hits the ground, there is maximum kinetic energy.
This question makes sense in the context of something like a pendulum. At the top of its swing, a pendulum is at maximum height, is not moving and so has zero kinetic energy, and has maximum potential energy since all its energy is potential. As it falls, it gradually moves with increasing speed, so its potential energy is being converted to kinetic energy. At the bottom of the swing, it is moving at maximum speed, and all its energy is kinetic, none is potential, Then it starts to move upwards again, and its kinetic energy is gradually converted back to potential energy.
Think of potential energy as stored energy, and kinetic energy as energy that puts an object in motion (i.e., increases the magnitude of velocity). In general you can set them equal to each other, to for example determine the velocity an object will be atLet U = kinetic energy and K = kinetic energyU = mgh (mass, gravity, height)K = (1/2)mv2 (mass, velocity)If you set U and K equal to each other.U = Kmgh = (1/2)mv2masses cancel out leaving you withv2= 2gh (or about 20h)The higher an object is from the surface of the ground, the more potential energy it has. Looking at the equation I listed, you can see velocity get's higher as height increases. The velocity in this equation is what velocity it would be at the instant the object hit the surface.
Yes - because an airplane and a bird both flying exist in a potential field field (gravity) and can be moved by that force, they both have potential energy. How much depends upon their altitude. As well, because they both have a velocity in forward flight, they both have kinetic energy.
Use the formula for kinetic energy: KE = (1/2) mv2 (one-half times the mass times speed squared). Clearly, the amount of kinetic energy depends both on the mass and on the speed of the object.
The height in meters and the velocity in m/s are needed.
Kinetic energy is at its maximum when the velocity of the ball is greatest. This will occur immediately upon release. Air resistance will slow the ball from this point and unless the ball falls back past its original starting height, it will never achieve a velocity greater than that with which it starts.
The ball has the highest gravitational potential energy when it is at its highest point in the air, as that is when it has a velocity of zero and is up the highest.
potential energy is typically measured as m*g*h which means that its a function of height. kinetic energy is .5*m*v^2 , which means kinetic energy is dependent on velocity. therefore if an object is at any altitude and has some velocity it has kinetic and potential energy
Kinetic energy is dependent on which point you are talking about. When it is about to be dropped, kinetic energy is zero. When it reaches almost hits the ground, there is maximum kinetic energy.
When a body is supported at a height, it has potential energy. When it is released, it will start to fall. As the downward velocity increases, so kinetic energy increases. The potential energy is reduced as the height of the body decreases.
This question makes sense in the context of something like a pendulum. At the top of its swing, a pendulum is at maximum height, is not moving and so has zero kinetic energy, and has maximum potential energy since all its energy is potential. As it falls, it gradually moves with increasing speed, so its potential energy is being converted to kinetic energy. At the bottom of the swing, it is moving at maximum speed, and all its energy is kinetic, none is potential, Then it starts to move upwards again, and its kinetic energy is gradually converted back to potential energy.
The ball has the highest potential energy at its maximum height (15m in the air). At the beginning, the ball has only kinetic energy and no potential energy. But as the ball travels upward, kinetic energy is converted into potential energy. When the ball changes direction, there is no kinetic energy, as all of it is now potential energy. As the ball returns back down, potential energy is converted back into kinetic energy.
Yes. Example: A ball thrown directly upwards; at any moment (except at its maximum height) it has velocity, and therefore kinetic energy. Also, at any moment (except when it touches the floor) it has gravitational potential energy (assuming you use the ground level as reference level).
that depends on what potential, whether we have to calc it using relativity theory, etc.. for a simple body near ground its kinetic energy: E_kin = 1/2 *m*v^2 m ist the mass, v its velocity potential energy: E_pot = m*g*h g is the gravity accelaration, h is height
Think of potential energy as stored energy, and kinetic energy as energy that puts an object in motion (i.e., increases the magnitude of velocity). In general you can set them equal to each other, to for example determine the velocity an object will be atLet U = kinetic energy and K = kinetic energyU = mgh (mass, gravity, height)K = (1/2)mv2 (mass, velocity)If you set U and K equal to each other.U = Kmgh = (1/2)mv2masses cancel out leaving you withv2= 2gh (or about 20h)The higher an object is from the surface of the ground, the more potential energy it has. Looking at the equation I listed, you can see velocity get's higher as height increases. The velocity in this equation is what velocity it would be at the instant the object hit the surface.
Speed is part of kinetic energy ... KE = 1/2 mv2 ( v is velocity, speed). Kinetic energy can be converted to potential energy, if done properly. Height is a factor of PE. PE = mgh (h is height). So an increase in KE, more speed, can be transformed into more height.