force = mass * acceleration = 2 * -9.82 = -19.64 newtons
work done = force * distance = -19.64 * 5.092 metres = -100 joules
when the object reaches maximum height, the velocity of the object is 0 m/s.It reaches maximum height when the gravity of the body has slowed its velocity to 0 m/s. If there is no gravity and there is no external force acting on it then it will never reach a maximum height as there wont be a negativeaccelerationdemonstrated by newtons first law.Where there is and you have the objects initial velocity then you can use :v^2 = u^2+2.a.sv = Velocity when it reaches Max. height so v = 0u = Initial Velocity (m/s)a = Retardation/ Negative Acceleration due to gravity, -9.80m/s ^2And then the unknown (s) is the displacement, or height above ground, and if everything else is in the right format it should be in metres.
The ball has the highest gravitational potential energy when it is at its highest point in the air, as that is when it has a velocity of zero and is up the highest.
initial velocity of the kick = 28.06 m/s
A model rocket reaches maximum velocity at the point where the thrust from the engine matches the drag from the air, or the point where the thrust goes to zero when the fuel burns out, whichever comes first.
The maximum height of a thrown ball is dependent on the upward portion of the initial velocity. Air friction will slow it somewhat but gravity will cause it to lose most of its upward velocity. The velocity will decrease by 9.8 m/sec for each second of its upward motion, until it reaches zero. At that point, the ball is pulled back toward Earth.
When it's at its maximum height its speed will be zero.
Velocity= sqrt(2(distance*gravity))
peak height = (take off velocity^2)/(2*gravity)
weight of the vehicle, height and width of the vehicle, gravity, size of the tires (amount in contact with the ground), and friction
This problem can be solved simply by using the following equation: Vf^2= Vi^2+2*a*d Vf = 0 at the maximum height Vi = 95 ft/s a = acceleration due to gravity = -32 ft/s^2 Plugging these in gives a maximum height from the beginning of the throw as: d= 141 ft However the ball started from a height of 145 ft so the ball reaches a maximum ht of 286 ft.
It reaches a maximum height of 10 to 20 feet
when the vertical component of its velocity is zero.