C8h18
The reactants are C8H18 and oxygen.
The chemical reaction is:2 C8H18 +25 O2 = 16 CO2 + 18 H2O
C8H18. I assume you mean how many moles octane in 16 grams. 16 grams C8H18 (1 mole C8H18/114.224 grams) = 0.140 moles octane
C8h18
No, C8H18 is not an aqueous solution. It is a chemical formula for octane, which is a hydrocarbon compound commonly found in gasoline.
With a bigger size there are stronger London forces. London forces are also known as Dispersion forces and van der Waal forces. These forces become stronger as the size of the molecule increases. Butane, C4H10, is a gas with a relative size of 58 and a boiling point of ~ -1 ºC. Octane, C8H18, is a liquid with a relative size of 114 and a boiling point of 125 ºC. The two molecules differ in size only but as octane is bigger it has a higher boiling point due to the dispersion forces.
Viscosity is proportional to the strength of intermolecular forces holding molecules together. Each of these molecules is non-polar, so the only intermolecular forces they have to hold each other together are dispersion forces (temporary dipole-dipole interactions caused by shifting electron clouds). The strength of dispersion forces depend on how easily the electron clouds shift. Molecules with more electrons have bigger electron clouds that are more likely to shift. Therefore, they are going to have the strongest intermolecular forces. So C16H34 should be the most viscous.
C8H18 bcz volatility depends upon intermolecular forces and alkanes have van der wall f.o.a and this force depends upon molar mass..Since c8h18 has lower molar mass so the force is less and intermolecular attraction is less.. So it can easily get vaporized . Therefore c8h18 is more volatile..
2 moles C8H18 (18 moles H/1 mole C8H18) = 36 moles of hydrogen =================
The reactants are C8H18 and oxygen.
octane + oxygen -------> carbon dioxide + water
Combustion of Octane: 2 C8H18 + 17 O2 --> 16 CO2 + 9 H2O
The chemical reaction is:2 C8H18 +25 O2 = 16 CO2 + 18 H2O
The chemical reaction is:2 C8H18 +25 O2 = 16 CO2 + 18 H2O
In organic chemistry, alkanes such as C8H18 have structural isomers. The more these isomers are branched the lower the boiling point is. The reason for this, is that un-branched alkanes have a higher mass area, they are more likely to have more potential points of attachments for other atoms or molecules which would then raise intramolecular forces thus increasing boiling points. The structural isomer of C8H18 that has the boiling point is systematically known as 2,2,3,3-tetramethylbutane.
C8H18. I assume you mean how many moles octane in 16 grams. 16 grams C8H18 (1 mole C8H18/114.224 grams) = 0.140 moles octane
yes. C8H18