... Current surges back and forth.
dc supply is used for control circuit because dc current is an independent source .
In dc equivalent circuit of an amplifier all capacitors are replaced by open circuit because capacitor block dc. As , Xc=1/2πfC We know that that frequency of dc is zero so Xc will infinite so we replace all capacitors with open circuit.
Yes, an inductor is a short circuit to dc...that's true....IF the inductor is an ideal one, that is, the inductor has no resistance but has inductance only. Anything in real world, as you know, is not ideal. An inductor is usually made of a copper wire. A copper wire has its own resistance. If an inductor coil is thin and long (i.e. many turns), it will provide an appreciable resistance to DC, and will no longer be a short circuit.
Including a series capacitor in the input and/or output circuit of the transistor. If the capacitor in the output circuit is omitted there will be a dc component in the output.
A DC ammeter will read zero
Capacitance will block DC
dc supply is used for control circuit because dc current is an independent source .
DC has no frequency.
to convert the DC into DC.............
yes definitely you can
No.
Transformers only work with alternating currents. So the answer is Yes, BUT it would have to be a DC Pulsing circuit. using flip flop circuit or a 555 circuit or chop circuit.
In the circuit where the DC motor is added, it was not specified whether the motor was added in series or in parallel to circuit elements. If it was added in series, it will increase circuit resistance and it will cause circuit current to go down. In parallel, the motor will reduce total circuit resistance, and circuit current will increase.
as it acts ideally as open circuit for dc
What supplies a dc motor is not current, but voltage. Current is what flows in the circuit formed by the dc motor and for the charge. That current varies according to the resistance of the circuit.
In dc equivalent circuit of an amplifier all capacitors are replaced by open circuit because capacitor block dc. As , Xc=1/2πfC We know that that frequency of dc is zero so Xc will infinite so we replace all capacitors with open circuit.
A short circuit.