H2o
To find how many grams of silver nitrate can be produced, first determine the limiting reactant. Calculate the moles of silver nitrate and calcium chloride in the given volumes and concentrations. The reactant that produces fewer moles of silver nitrate will be the limiting reactant. Then use stoichiometry to find the amount of silver nitrate that can be produced from the limiting reactant.
Ca(ClO3)2 ---> CaCl2 + 3O2 is the balanced equation when calcium chlorate is heated.
Ca+O=CaO
The equation for heating calcium carbonate (CaCO3) is CaCO3(s) → CaO(s) + CO2(g). Heating calcium carbonate decomposes it into calcium oxide and carbon dioxide.
The balanced equation for calcium reacting with oxygen gas is: 2Ca + O2 -> 2CaO.
To determine the limiting reactant, calculate the moles of each reactant using their molar masses. Then, use the stoichiometry of the reaction to determine which reactant will be consumed first. Whichever reactant produces the lesser amount of product will be the limiting reactant.
The balanced chemical equation for the reaction between calcium and chlorine gas to produce calcium chloride is: Ca + Cl2 -> CaCl2. From this equation, we can see that one mole of calcium reacts with one mole of chlorine gas to produce one mole of calcium chloride. The molar mass of calcium is 40.08 g/mol and the molar mass of chlorine gas is 70.90 g/mol. This means that 10.0 grams of calcium is equivalent to 0.249 moles of calcium and 20.0 grams of chlorine gas is equivalent to 0.282 moles of chlorine gas. Since the ratio of calcium to chlorine gas in the balanced chemical equation is 1:1, this means that 0.249 moles of calcium would react completely with 0.249 moles of chlorine gas, leaving an excess of 0.033 moles (or 2.34 grams) of chlorine gas. The limiting reactant in this reaction is calcium, and the maximum amount of calcium chloride that can be produced is equivalent to the number of moles of the limiting reactant, which is 0.249 moles (or 27.8 grams) of calcium chloride.
The best way to answer this question is with an example. Using Calcium oxide reacting with hydrochloric acid, the reaction formula is: CaO + 2HCl ----->CaCl2 + H2O The molecular weight for Calcium Oxide is 56, for Hydrochloric acid is 26.5 and for calcium chloride 110. If you start with only 56g of Calcium oxide but say 10000g of hydrochloric acid, the maximum yield of the product calcium chloride can only ever be 110g. It does not matter how much hydrochloric acid is added. The limiting reactant in this example is the calcium oxide.
The presence of calcium oxalate and water passing through the filter paper due to its porosity will lead to a lower reported percentage of the limiting reactant. This is because some of the product is lost during the filtration process, resulting in an underestimate of the actual amount of product formed.
Ca(ClO3)2 ---> CaCl2 + 3O2 is the balanced equation when calcium chlorate is heated.
The word equation for calcium sulphide is: calcium + sulphur -> calcium sulphide.
The word equation for calcium oxide is: calcium oxide + water → calcium hydroxide.
There cannot be a balanced chemical formula for just a compound of something. You need a reactant to produce a product in order to balance an equation. In this case, you can get a chemical formula by this chemical name: calcium hydrogen carbonate. Since calcium has a +2 charge and hydrogen carbonate has a -1 charge, you need two hydrogen carbonates for every one calcium ion. The chemical formula is: Ca(HCO3)2.
The chemical equation for the reaction between boron and calcium is: 3Ca + 2B -> 3CaB2.
Adding calcium to water is a physical change because it does not alter the chemical composition of either the calcium or water molecules. The calcium simply dissolves in the water to form calcium ions and does not undergo a chemical reaction.
The word equation for the reaction between hydrochloric acid and calcium is: hydrochloric acid + calcium → calcium chloride + hydrogen gas.
Calcium (Ca) is element. O2 and CaO are molecules.