By Electrolysis
Na+, but there is no such thing as NaCI, it is NaCl , simple table salt
The cation, or positively charged ion, in NaCl is Na+.
The equation is: NaCl----------Na++ Cl-
NaCl---------------→Na+ + Cl-
Na+ + Cl- --> NaCl NaCl = salt.
Neither, NaCl is a simple ionic compound that dissolves completely in water yielding a neutral solution. Na+ is the cation and Cl- is the anion.
NaCl --> Na+ + Cl- You could write water on either side I suppose, but it is negligible. I've also seen H2O written over the arrow.
Any reaction occur between these two reagents.
[348 (g NACl)] * [23 (g/mol Na)] * [1 (mol NaCl/mol Na)] / [58.5 (g/mol NaCl)] = [348*23/58.5] = 136.8 = 137 g Na
Since NaCl is composed of one Na atom and one Cl atom, and the molar mass of Na is roughly 23 g/mol while that of Cl is about 35.5 g/mol, the molar mass of NaCl is approximately 58.5 g/mol. In 100 ppm NaCl, there are 100 mg of NaCl in 1 kg of solution. Therefore, the amount of Na in 100 ppm NaCl would be 100 mg * (23 g Na / 58.5 g NaCl) = ~ 39.3 ppm Na.
No, a 100 ppm NaCl solution means there are 100 parts per million of NaCl (sodium chloride) in the solution, not just sodium (Na) alone. To calculate the amount of sodium ions (Na+) in the solution, you would need to consider the molar mass of NaCl and the percentage of Na+ in NaCl.
In NaCl, the molar mass of Na is 22.99 g/mol and Cl is 35.45 g/mol. Therefore, the molar mass of NaCl is 58.44 g/mol. Given 8.0g of NaCl, the mass is distributed between Na and Cl in a 1:1 ratio. Thus, there are 3.5g of Na in 8.0g of NaCl.