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Which resistor had the smallest current through it when the v was 12v?
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What is the current flow if you apply 12v across a 68 ohm resistor?
0.1764 amps
How much resistance required to convert 12V DC to 10.5V DC?
How much current? Volts/Amps = Ohms. In your case Volts = 1.5
What value of resistor will be needed to produce the current of 100mA when a voltage of 12V is applied across the resistor?
R = E/I = (12)/(0.1) = 120 ohms(Make it a big one. It dissipates I2R = 0.01 x 120 = 1.2 watts.)
2ohm and 4ohm resistor are connected in series to a 12V battery what is the current through each resistor and use Ohm's law 2 show that the voltage drops across the individual resistors add up to 12V?
To answer this question, you need not only Ohm's law, but also Kirchoff's current and voltage Laws.Kirchoff's current law say the current at every point in a series circuit is the same. Lets call that current i.Ohm's law say voltage is resistance times current. That means the voltage across each resistor R1 and R2 is V1 = R1i and V2 = R2i.Kirchoff's voltage law says that the signed voltage drops around a series circuit add op to zero. This means that the voltages V1 and V2 must add up to be be equal to 12. This means that R1i + R2i = 12. This means that i = 12/(R1 + R2). But, hey, you say, this is just Ohm's law! This means that the current through the circuit is 2A. It also means that the resistance of two resistors in series is simply the sum of their resistance.Now that we know the current, we can calculate each resistor's voltage. V1 = R1i = (2)(2) = 4, and V2 = R2i = (4)(2) = 8. Crosscheck 4 + 8 = 12, so the two voltages do add up to twelve volts, as expected.In summary: The current through both resistors is 2A. The voltage across the 2 ohm resistor is 4V. The voltage across the 4 ohm resistor s 8V.
What will be the amps of a 12v 2amp circuit if there is a 12ohm resistor on it?
The formula you are looking for is I = E/R. Amps = Volts/Resistance. If you say it is normally a 2 Amp circuit, it normally draws 2 amps. Therefore the original resistance offered to the 12v battery is 2/12 = 6 Ohms. If you then connect a 12 Ohm resistor in series, they are added, so R = 18 Ohms. Now if you put 12v across this circuit it will draw 12/18 = 0.66 Amps. Or If you just put a 12 Ohm resistor across the 12v supply it will draw 1 Amp. If the circuit is protected by a 2 Amp fuse, it will not blow, but the resistor will get hot.
A 10 ohms resistor is connected aross a 12 volt battery How much current is there through the resistor?
Voltage = Current * ResistanceVoltage = 12VResistance = 10 ohmsCurrent = Voltage/ResistanceCurrent = 12V/10 ohmsCurrent = 1.2 Amps
What is the current flow if you apply 12v across a 68 ohm resistor?
0.1764 amps
What does the resistance in an electrical circuit limit?
Current flow. It's also worthy of noting that a resistor doesn't limit-by, it limits-to, and the current is dependent on the voltage. I[A] = U[V] / R[ohm] It's also worth to note, that the power flowing through said resistor with resistance R is I[A] * U[V] for DC circuits - helps to remember this well when picking appropriately-rated resistors for replacement. Example: let's say we have a 20-ohm, 2W resistor. If we place it in a circuit with 5V, we will get 5V / 20ohm = 250mA (0.25A) of current flowing through the resistor. The power the resistor will "see" is 250mA * 5V = 1.25W, so it's safe. But let's now put that same resistor in a 12V circuit. The current flowing will be 12V / 20ohm = 600mA (0.6A), and the power will be 600mA * 12V = 7.2W, so the resistor will burn.
What current will flow if 12v is put across a 12ohms resistor?
V = ir i = v/r i = 12/12 i = 1a
Convert 12v to 3v DC?
if you have 12v dc then you can use a 4 ohm resistor
When a 12 V battery is connected across an unknown resister there is a current of 2.5 mA in the circuit find the value of the resistance of the resistor?
Resistance = voltage / current = 12V / 2.5mA = 12V / (2.5 x 10-3 A) = 4.8 x 103 ohm
How much resistance required to convert 12V DC to 10.5V DC?
How much current? Volts/Amps = Ohms. In your case Volts = 1.5
What is the unit of the resistors?
Resistor values are given in ohms. A value may be selected to deliver a specific current at a given voltage. This is given in what is known as Ohm's Law where: Voltage (V) = Current (A) X Resistance (Ohm) A 12ohm resistor placed across a 12V battery would pass 1Amp of current and put out 12W of heat.
What value of resistor will be needed to produce the current of 100mA when a voltage of 12V is applied across the resistor?
R = E/I = (12)/(0.1) = 120 ohms(Make it a big one. It dissipates I2R = 0.01 x 120 = 1.2 watts.)
What is the voltage of a battery that can create a 1.5 amp through an 8 ohm resistor?
V = I.R V = 1.5 x 8 V = 12V
What is the unit of measures for resistors?
Resistor values are given in ohms. A value may be selected to deliver a specific current at a given voltage. This is given in what is known as Ohm's Law where: Voltage (V) = Current (A) X Resistance (Ohm) A 12ohm resistor placed across a 12V battery would pass 1Amp of current and put out 12W of heat.
What resistors are required to convert 12volts Dc to 3 volts dc?
In general terms, the voltage across a resistor can be calculated by ohms law: V = I . R voltage across the resistor = current through the resistor multiplied by the value of the resistor. So, if the resistor has a value of 100 ohms and the current flowing through the resistor is 10mA then the voltage across the resistor will be 100 x 0.01 = 1 volt. If the current flows through two resistors connected in series, the voltage will be split over the two resistors according to their resistance. V = V1+V2 = I . R1 + I . R2 You want V2/(V1+V2)=3V/12V Using Ohm's law for each voltage: V2/(V1+V2) = I . R2 / (I . R1 + I . R2) = R2 / (R1+R2) You see that the answer to your question is: Any combination of resistors will do the job, provided that R2/(R1+R2) = 3V/12V e.g. R2=3Ohm and R1=8Ohm or R2=3000Ohm and R1=8000Ohm Depending on your choice, you will get a different current flowing. In the real world you might need to control the current flowing into your circuit. For example if the device to be powered is a 3V LED and the required current is 15mA then we can calculate as follows: 12V - 3V = 9V. 9V = 0.015A x R Therefore R = 9V / 0.015A Therefore R = 600 ohms. However, in real life this is usually a terrible way to control voltage for several reasons. First, because the current in the most circuits is not constant (it would be constant for an LED but not for most gadgets). Second, this method wastes energy heating the resistor. Third, it is often not possible to find a resistor of exactly the right value. So, in real life this problem is usually solved by using a "voltage regulator" which is a simple integrated circuit (often with just three legs).
