abc
It is possible.
Take a rhombus ABCD. A rhombus as 4 equal sides, thus AB = BC = CD = DA Draw in 1 diagonal AC. This splits the rhombus into 2 triangles. ABC and CDA with side AB = CD, BC = DA and AC common to both triangles. Thus ABC and CDA are congruent by Side-Side-Side. Triangles ABC and CDA are isosceles triangles since they have two equal sides (AB = BC and CD = DA) thus angles DAC = DCA = BAC = BCA. Specifically DAC = BAC. But DAC + BAC = DAB, thus DAC = BAC = ½ DAB; similarly DCA = BCA = ½ BCD = ½ DAB Drawing in the other diagonal BD, the same arguments show triangles ABD and CDB are congruent and angles ADB = CDB = ABD = CBD = ½ ABC Let the point where the diagonals meet be E. We now have 4 triangles ABE, BCE, CDE and DAE with equivalent angles and sides: Angles DAE* = BAE = BCE = DCE (= ½ DAB) Angles ABE = CBE = CDE = ADE (= ½ ABD) Sides AB = BC = CD = DA Thus the 4 triangles are congruent by Angle-Angle-Side. *Angle DAE = DAC since E lines along AC; similarly for all the other angles involving point E, ie angle BCE = BCA, ADB = ADE, etc
First draw a triangle with vertices A, B, and C. Let's let C be at the top and B and A the base of the triangle. A' and B' are on the line drawn parallel to the base and through point vertex C. Place A' on the right of C and B' on the left of C. Of course it works for any triangle, but I am trying to make the picture easy so then you can generalize.if ABC is a triangle then
6 -- abc, acb, bac, bca, cab, cba
The triangle ABC is an equallateral triangle since angle ABC is one sixth of 360 degress of the circle and the angles BAC and BCA are equal of the remaining 180-60=120 degrees. With radius BC (or BA) being 6; the areaof the circle is pi (r)squared; 36 piArea of the circle is 36piMalcolm Lowe
Any 3 from 6 is 6!/(3! x 3!) ie 720/36 which is 20: ABC/ABD/ABE/ABF/ACD/ACE/ACF/ADE/ADF/AEF/ BCD/BCE/BCF/BDE/BDF/BEF/CDE/CDF/CEF/DEF. If the order in which they can run is taken into account then that 20 must be multiplied by 6 viz: ABC/ACB/BAC/BCA/CAB/CBA etc
Right Hand: G, F#, G, E, G, F#, G, E, B, A, B, G, B, A, B, G, E, E, D, C, B, B, A, G, A, A, B, A, G, E, E, Left Hand: D, C, B, A, E, G, A, E This is how I play Carol of the Bells
i will do mca after bca
BCA sort codes
BCA Semarang
yes.you can