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Calculate the final concentration (in Molarity) when 25 mL of water is added to 95 mL of 1.4 M LiCl.?
25 ml added to 95 ml give a final volume of 120 ml (95 ml)(1.4 M) = (120 ml)(x M) x = 1.1 M
If you have 0.05 ml of an undiluted culture at a concentration of 3.6x10 6 CFU ml You then add 4.95 ml sterile diluent What is the dilution factor and what is the final concentration of cells?
The dilution factor is 1:100, as you're adding 4.95 ml to the original 0.05 ml. The final concentration is calculated by multiplying the original concentration by the dilution factor, resulting in a final concentration of 3.6x10^4 CFU/ml.
What is the final concentration if 100 mL of water is added to 25.0 mL of 6.0 M NaCl?
We must first figure out the amount of NaCl in moles: M = mol/L = mmol/mL 6 = mmol/25 mL 150 mmol NaCl Now divide by the total volume to get the final concentration: 150 mmol/100 mL = 1.5 M NaCl
What is the final volume of a gas with an initial volume of 75 mL if the pressure decreases from 300 m to 200 mL?
What? Pressure cannot be measured in m or in mL. Please check you homework and resubmit the correct question.
If you have a 100.0-mL graduated cylinder containing 50.0 mL of water. You carefully place a 129-g piece of brass of density 8.56 gmL into the water. What is the final volume reading in the cylinder?
The water will rise by the volume of the brass: volume = mass/density = 129g / 8.56 g/ml ≈ 15.1 ml → final reading ≈ 50.0 ml + 15.1 ml = 65.1 ml
What is the final change in the volume of juice from this carton if Sara poured 150 ml of juice into a cup and 175 ml into another cup?
It is 325 ml.
What will be the final pH if you mix 500 ml of water with the water of 500 ml having pH 7?
7
What is the volume of an object when after dropping 17.8 mL water in a graduated cylinder rises to 23.6 mL?
The volume of the object is 5.8 mL. This can be calculated by subtracting the initial volume (17.8 mL) from the final volume (23.6 mL).
A student carefully diluted 25.0 ml 0.6 M NaOH solution in 475 ml of distilled water What is the molarity of the diluted solution of base?
Assuming that the 25.0 ml are added to the 475 ml of water, not diluted to that volume:Moles of NaOH in the original 25 ml = 25/1000 x 0.6 = 0.015 moles Final volume = 25 + 475 ml = 500 ml. We have 0.015 moles in 500 ml, so 0.03 moles in a litre, Molarity = 0.03.
When 0.25ml is diluted to 20ml the resulting dilution is?
When 0.25 ml is diluted to a final volume of 20 ml, the resulting dilution can be calculated as the ratio of the original volume to the final volume. This is calculated as 0.25 ml / 20 ml, which simplifies to a dilution factor of 1:80. Therefore, the resulting dilution is 1:80.
If 400.0 mL of 0.420 M NaCl are mixed with 110.0 mL of 0.240 M NaCl what is the molarity of the final solution?
In 400 ml of the 0.420 M NaCl there are 0.1680 moles of NaCl.In 110 ml of the 0.240 M NaCl there are 0.0264 moles of NaCl.There are 0.1944 moles of NaCl in 510 ml of solution. Dividing 0.1944 moles by 0.510 l gives 0.381 mole/l.So You get a 0.381 M NaCl.
A 100 ml sample of nitrogen at 810 torr was compressed to a volume of 72 mL in a syringe What was the pressure of trapped nitrogen in torr?
To find the final pressure of the nitrogen, we can use Boyle's Law which states that the pressure and volume of a gas are inversely proportional when temperature is constant. Therefore, 100 mL * 810 torr = 72 mL * final pressure. Solving for final pressure, we get: final pressure = (100 mL * 810 torr) / 72 mL = 1125 torr. So, the pressure of the trapped nitrogen in the syringe is 1125 torr.
