We must first figure out the amount of NaCl in moles:
M = mol/L = mmol/mL
6 = mmol/25 mL
150 mmol NaCl
Now divide by the total volume to get the final concentration:
150 mmol/100 mL = 1.5 M NaCl
diffusion coefficient nacl in water at difrent concentration
An acid (HCl) added to an alkali/base (NaOH) forms a salt (NaCl) and water : HCl + NaOH ----> NaCl + H2O
14.625
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It depends on the final solution Volume you want to prepare. For 100ml of a 6M NaCL solution, you add 35.1g of NaCl to water until you reach 100ml. Dissolve and autoclave for 15 mins.
Increase the concentration of NaCl evaporating the water.
When NaCl is added to water, you would observe that it dissolves quite readily.
The concentration of NaCl is 263 g/L
The concentration of NaCl is 15,73 mg/100 mL.
This concentration of NaCl is 2,6 g NaCl/100 mL solution.
After a concentration of 360,9 g/L a saturate solution of NaCl is formed.
The answer is 29,22 g NaCl.
Concentration = Molarity = mol/L24 g NaCl = ?? mol NaCl?? mol NaCl/2 L water = ?? M (M is unit of molarity)
diffusion coefficient nacl in water at difrent concentration
A supersaturated solution of sodium chloride in water at 20 oC appear after a concentration of 360 g NaCl/L water.
This concentration is min. 150 mmoles/L NaCl.
Yes. When NaCl is added to water, it forms a solution, which is a homogeneous mixture.