Increase the concentration of NaCl evaporating the water.
You could titrate equal volumes of 1M solution of NaOH and 1M solution of HCl to obtain 1M solution of NaCl.
Your answer is 2. 1m = 100cm 1cm = .01m
6.9 m = 6.9m * 1m/1m = 6.9m * 100cm/1m = 6.9 * 100cm = 690 cm
Let's see. NaOH + HCl = NaCl + H2O The usual salt ( NaCl ) and water.
1 mole of NaCl is 58.44 g 200 g NaCl * (1 mol NaCl/58.44 g NaCl) = 3.422 mol NaCl There are about 3.4 moles in 200 grams of NaCl.
1mEq NaCl = 58,4 mg NaCl
1 cm is .01m so 600cm*.01m = 6m =] -ray
100cm = 1m 1cm = 1m/100 472cm/100cm/m = 4.72m
just multiply it with 1m.
100cm = 1m 1 meter
1m = 100cm13 * 100 = 1300cm
1m = 100cm 890m = 89000cm