You could titrate equal volumes of 1M solution of NaOH and 1M solution of HCl to obtain 1M solution of NaCl.
Put 0.9g of Nacl in a beaker and add distilled water to make up to 100ml. that is 0.9% Nacl (Normal saline Solution) From Tade Olubunmi Ademola
yes, as solvent evaporate only solute will left behind with little solvent.thus solution will become more saturated. for example NaCl dissolve in water.after evaporation of some water the remaining solution will be saturated.
Not exactly. Saline solution is sterilized and is a dilution of sodium chloride (NaCl) - meaning that the NaCl is dissolved in deionized water. The solution is 9 grams of sodium chloride (NaCl) dissolved in 1 liter of water.
Molarity = moles of solute/Liters of solution Molarity = 0.250 moles NaCl/2.25 Liters = 0.111 M NaCl --------------------
no
You have to evaporate (by open boiling) 45 mL of the 75 mL 2M NaCl solution thus reducing the volume to 30 mL 5M NaCl.
Dissolve 100 mg NaCl in 1.0 Litre water.
A solution of NaCl 1 M.
Dilute it.
By a slowly evaporation of water from a NaCl solution.
Dissolve 2g of NaCl in 100 cm3 water at normal temperature.
To prepare a 0.9% solution take 0.9grams NaCl and dilute with 100mls of water.
Increase the concentration of NaCl evaporating the water.
It depends on the final solution Volume you want to prepare. For 100ml of a 6M NaCL solution, you add 35.1g of NaCl to water until you reach 100ml. Dissolve and autoclave for 15 mins.
The volume is 342 mL.
40 grams, this is the 1M NaOH standard laboratory solution.
Dissolve 30g of sodium chloride in 100 mL of water.