The answer is 29,22 g NaCl.
The answer is 25 g/L.
Sodium chloride is the solute and the concentration is 55,8 g/L.
The answer is 28,81 %.
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Concentration = Molarity = mol/L24 g NaCl = ?? mol NaCl?? mol NaCl/2 L water = ?? M (M is unit of molarity)
Not exactly. Saline solution is sterilized and is a dilution of sodium chloride (NaCl) - meaning that the NaCl is dissolved in deionized water. The solution is 9 grams of sodium chloride (NaCl) dissolved in 1 liter of water.
1,574 mol/L NaCl
Molarity = moles of solute/Liters of solutionGet moles NaCl.58.44 grams NaCl (1 mole NaCl/58.44 grams)= 1 mole NaCl------------------Molarity = 1 mole NaCl/1 liter= 1 M NaCl========
This measure is the concentration of NaCl expressed in mol/L, g/L, g/100 g (percentage).
This measure is the concentration of NaCl expressed in mol/L, g/L, g/100 g (percentage).
This measure is the concentration of NaCl expressed in mol/L, g/L, g/100 g (percentage).
This depends on the volume and concentration of this solution.
According to the CRC Handbook of Chemistry and Physics, 58th Edition, 35.7 grams of sodium chloride (NaCl) can be dissolved in 100.0 grams of pure water at 0 degrees centigrade (page B-159). At 199 degrees centigrade the amount able to be dissolved increases to 39.12 grams of NaCl.