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The precipitate is copper(II) hydroxide. The chemical reaction is:2 NaOH + CuSO4 = Cu(OH)2 + Na2SO4
Methyl orange shows yellow color in an NaOH solution.
The chemical equation is:3 NaOH + FeBr3 = 3 NaBr + Fe(OH)3
Nothing - barium chloride is soluble. You can however precipitate either the barium (e.g. with sodium sulphate, giving barium sulpate, or the chloride, e.g. with silver nitrate giving silver chloride precipitate.
No. Not every double displacement reaction is a precipitation reaction. If we look at just one reaction, a neutralization reaction between hydrochloric acid (HCl) and sodium hydroxide (NaOH), we'll see this: HCl + NaOH => NaCl + H2O The end products are sodium chloride (NaCl, or table salt) and water (H2O). The salt is soluble in water so it will not precipitate out. There are many, many double displacement reactions, and the ones that will result in a precipitate will be ones where an end product is not soluble.
The precipitate is Mg(OH)2.
Copper hydroxide is the precipitate.
Yes. Silver hydroxide (AgOH) will precipitate out of solution.
C6H5COOH + NaOH + I2 -----------> C6H5COOI + NaI + H2O
I got a thick white precipitate from AgNO + NH3 on the other hand, I did get a brown precipitate when mixing AgNO3 with NaOH
CH3I + COONa + 3NaI + 3H20
AgNO3 + NaOH = AgOH + NaNO3 The silver hydroxide is an insoluble precipitate but also unstable: 2 AgOH----Ag2O + H2O
SrCl2 + 2NaOH --> 2NaCl + SR(OH)2
Sodium Hydroxide (NaOH)and starch
The precipitate is copper(II) hydroxide. The chemical reaction is:2 NaOH + CuSO4 = Cu(OH)2 + Na2SO4
The net ionic equation for NaOH and Na2SO4 when they form a precipitate is simple. It will contain only the atoms that participate in the reaction. Both of these compounds are soluble.
Methyl orange shows yellow color in an NaOH solution.