By having a minimum current in your current loop it is possible to detect when there is a fault in the line or the device at the other end has been disconnected. If these errors conditions occur, the current falls to zero, which should never happen in normal operation.
A: Assuming 100% efficiency 320 ma
There are .42 amps in 420 mA. Equation 420/1000 = .42 amps
Because 4-20ma is an industry standard.
Yes, the output current (measured in mA or Amps) on chargers for electronics matters, as it determines how quickly the device can be charged. Higher output currents typically result in faster charging times, but it's important to ensure that the device being charged can handle the higher current to prevent damage.
A CR1216 battery typically has a capacity of around 40 mAh, but its output current in milliamps (mA) can vary depending on the specific application and load. Generally, these batteries can deliver a current of about 5 to 20 mA for short periods, but for continuous use, the current draw should be lower to avoid rapid depletion. Always refer to the manufacturer's specifications for precise details on current output and capacity.
mA stands for milliampere and it is a unit of measurement used to quantify the amount of electrical current flowing in a circuit. In the context of chargers, mA typically refers to the charging speed or current output of the charger, with higher mA values indicating a faster charging rate.
mA stands for mili-Amp, or one-thousandth of an Amp (or Ampere; being the unit of measure of current, or charge carriers; ie electrons in a circuit) 1 mA = 0.001 A
No, Your original adaptor has an output of 3 amps or 3000 ma. As you can see, the one you want to use for a replacement adaptor only has 1000 ma output, one third of the current capacity that you need.
The mechanical advantage (MA) of a lever is calculated by dividing the input arm length by the output arm length. In this case, the MA would be 36cm (input arm) divided by 6cm (output arm), resulting in a MA of 6.
The mechanical advantage (MA) is calculated as the ratio of the output force to the input force, or the distance the input force acts over compared to the distance the output force moves. The formula for mechanical advantage is MA = output force / input force = input distance / output distance.
Yes. (For any pairing of power supply and device, as long as the voltages are a match (in your case: 9v), and the output (in amps or milliamps (A or mA) of the power supply IS EQUAL TO OR GREATER THAN the current required by the device (in your case 1300mA or higher) then you will be fine. Yes it is suitable: The OUTPUT VOLTAGE (5v, 9v, 12v, etc) of a power supply MUST BE EQUIVALENT to the required voltage of the device to which it is to be connected, whereas the output CURRENT (500mA, 1A, 1500mA, 2A... etc) offered by the power supply MUST BE AT LEAST EQUAL TO OR GREATER THAN the current required by the device to which it is to be connected. (in your case, for example, as long as the power supply is rated at 9v, you could use one that has a rating of 1300mA, 1400mA, 1500mA, 1A...and so-on, without any damage to either device)
Supply voltage (VCC) 4.5 to 15 V Supply current (VCC = +5 V) 3 to 6 mA Supply current (VCC = +15 V) 10 to 15 mA Output current (maximum) 200 mA Maximum Power dissipation 600mW Power consumption (minimum operating) 30mW@5V, 225mW@15V Operating temperature 0 to 70 °C