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What else can I help you with?
What is the turns ratio of a transformer with a primary current of 25 mA and a secondary current of 300 mA?
300 / 25, or 12/1.
What current does the input required to give an output on Lm741?
It depends on the shunt feedback resistor on the op-amp, for example with a 10k feedback resistor connecting the output to the inverting input, 1 mA input current gives 10 volts signal output. The input terminal stays near zero voltage because of the high open-loop gain of the op-amp, so the inverting input is termed a 'virtual earth'.
What is the increase of current when 15-volts is applied to 10000-ohms rheostat which is adjusted to 1000-ohms value?
To find the increase in current when 15 volts is applied to a 1000-ohm rheostat, we can use Ohm's Law, which states ( I = \frac{V}{R} ). With 15 volts applied and the resistance set to 1000 ohms, the current is ( I = \frac{15V}{1000\Omega} = 0.015A ) or 15 mA. If the rheostat was previously at a higher resistance (10,000 ohms), the current would have been ( I = \frac{15V}{10000\Omega} = 0.0015A ) or 1.5 mA. Thus, the increase in current is ( 15 mA - 1.5 mA = 13.5 mA ).
What happens with voltage and current by damaged diode...the diode is IN5408?
It depends on how the diode is damaged. There are generally two cases. One, the diode is shorted, and conducts with a low impedance in both directions. The other, the diode is open, and does not conduct, having a high impedance, in both directions. The effect depends on the particular circuit. In a power supply, a shorted diode will often blow the fuse, while an open diode will result in no output, or in high ripple voltage output. Is it possible that diode has normal voltage output but wrong current,meaning low mA?
The power cube transformer for a portable CD player has an output of 4.6 V and 600 mA when plugged into a 120V per 60Hz outlet What is the peak current in the primary coil?
To find the peak current in the primary coil, we can use the power equation. The output power is (P = V \times I = 4.6 , \text{V} \times 0.6 , \text{A} = 2.76 , \text{W}). Assuming the transformer is ideal and neglecting losses, the input power in the primary coil is also 2.76 W. The primary voltage is 120 V, so the primary current (RMS) is (I_p = \frac{P}{V} = \frac{2.76 , \text{W}}{120 , \text{V}} = 0.023 , \text{A} ) (or 23 mA). The peak current is given by (I_{peak} = I_{rms} \times \sqrt{2} \approx 0.023 , \text{A} \times 1.414 \approx 0.0325 , \text{A} ) (or 32.5 mA).
What is input current if output voltage is 48V and output current is 350 mA and load of 15Watt?
A: Assuming 100% efficiency 320 ma
How many amps are in 420 mA?
There are .42 amps in 420 mA. Equation 420/1000 = .42 amps
Does MA output on chargers for electronics matter?
Yes, the output current (measured in mA or Amps) on chargers for electronics matters, as it determines how quickly the device can be charged. Higher output currents typically result in faster charging times, but it's important to ensure that the device being charged can handle the higher current to prevent damage.
How many mA does a 3volt CR1216 battery produce?
A CR1216 battery typically has a capacity of around 40 mAh, but its output current in milliamps (mA) can vary depending on the specific application and load. Generally, these batteries can deliver a current of about 5 to 20 mA for short periods, but for continuous use, the current draw should be lower to avoid rapid depletion. Always refer to the manufacturer's specifications for precise details on current output and capacity.
What does mA mean on chargers?
mA stands for milliampere and it is a unit of measurement used to quantify the amount of electrical current flowing in a circuit. In the context of chargers, mA typically refers to the charging speed or current output of the charger, with higher mA values indicating a faster charging rate.
What is mA output?
mA stands for mili-Amp, or one-thousandth of an Amp (or Ampere; being the unit of measure of current, or charge carriers; ie electrons in a circuit) 1 mA = 0.001 A
Why 4-20 mA why not 0-16 mA for current output?
By having a minimum current in your current loop it is possible to detect when there is a fault in the line or the device at the other end has been disconnected. If these errors conditions occur, the current falls to zero, which should never happen in normal operation.
Can I use an adaptor that has output of 12 volts 1000 ma to replace an adaptor has 12 volt 3 amps?
No, Your original adaptor has an output of 3 amps or 3000 ma. As you can see, the one you want to use for a replacement adaptor only has 1000 ma output, one third of the current capacity that you need.
A lever has 36cm input arm and 6cm output arm. What is the MA?
The mechanical advantage (MA) of a lever is calculated by dividing the input arm length by the output arm length. In this case, the MA would be 36cm (input arm) divided by 6cm (output arm), resulting in a MA of 6.
Mechanical advantage formula?
The mechanical advantage (MA) is calculated as the ratio of the output force to the input force, or the distance the input force acts over compared to the distance the output force moves. The formula for mechanical advantage is MA = output force / input force = input distance / output distance.
Can you use a 9v 1500ma on 9v 500ma device?
Yes. (For any pairing of power supply and device, as long as the voltages are a match (in your case: 9v), and the output (in amps or milliamps (A or mA) of the power supply IS EQUAL TO OR GREATER THAN the current required by the device (in your case 1300mA or higher) then you will be fine. Yes it is suitable: The OUTPUT VOLTAGE (5v, 9v, 12v, etc) of a power supply MUST BE EQUIVALENT to the required voltage of the device to which it is to be connected, whereas the output CURRENT (500mA, 1A, 1500mA, 2A... etc) offered by the power supply MUST BE AT LEAST EQUAL TO OR GREATER THAN the current required by the device to which it is to be connected. (in your case, for example, as long as the power supply is rated at 9v, you could use one that has a rating of 1300mA, 1400mA, 1500mA, 1A...and so-on, without any damage to either device)
Data specification of 555 timer ic?
Supply voltage (VCC) 4.5 to 15 V Supply current (VCC = +5 V) 3 to 6 mA Supply current (VCC = +15 V) 10 to 15 mA Output current (maximum) 200 mA Maximum Power dissipation 600mW Power consumption (minimum operating) 30mW@5V, 225mW@15V Operating temperature 0 to 70 °C
