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4s-orbital will be filled prior to 3d-orbital.

ORBITAL

n

l

(n+l)

4s

4

0

4+0 = 4

3d

3

2

3+2 = 5

Since 4s-orbital has least value of (n+l), therefore ,it will occupy electrons before

3d-orbital.

The order of increasing of energy of orbitals can be calc. from(n+l) rule or 'Bohr bury rule' According to this rule, the value of n+l is the energy of the orbital and such on orbital will be filled up first. e.g. 4s orbital having lower value of(n+l) has lower energy than 3d orbital and hence 4s orbital is filled up first. For 4s orbital, n+l=4+0=4 For 3d orbital, n+l=3+2=5,therefore 4s orbital will be filled first.

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Q: Why 4S orbital is filled before 3d orbital during writing electronic configuration Explain with the help of n l rule?
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Related questions

How would I find the electron configuration for carbon?

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"Noble gas configuration" means that in writing out an electron configuration for an atom, rather than writing out the occupation of each and every orbital specifically, you instead lump all of the core electrons together and designate it with the symbol of the corresponding noble gas on the periodic table (in brackets). For example, the noble gas configuration of nitrogen is [He]2s22p3


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