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In some cases, electron configurations will break the diagonal rule. This is because electron shells are most stable when fully filled or half-filled. Since the 3d sublevel can hold up to 10 electrons, 3d would be most stable with 10 or 5 electrons. To make this happen, an electron must move from the previous sublevel (4s) into the 3d sublevel. Consequently, both shells now have half-filled electron configurations. You should never take two electrons away from an s-shell to make a d-shell half full because then there would be more than 8 valence electrons (13, in fact), which is a hefty violation of the octet rule.
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∙ 13y ago
The electronic configuration of atoms is based on the filling of orbitals. In the case of the 4s orbital, it is relatively lower in energy than the 3d orbital, so it is filled first. Therefore, the 4s orbital can accommodate a maximum of 2 electrons. As for the 3d orbitals, they have a higher energy level and can accommodate a maximum of 10 electrons, but in the case of transition metals, only 5 electrons fill the 3d orbitals due to electron configuration stability.
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When comparing the energy of an electron in the 3d sub-level to that of an electron in the 4s sublevel of the same atom?
They are both capable of holding a maximum of 10
Why zinc is not a noble gas since its electron configuration is 3d10?
It has two valance electrons. Abbreviated electron configuration. [Ar] 3d^10 4s^2 ( energy wise that would be 4s^2 3d^10 )
Why does an element lose 4S electrons before 3D electrons?
Because 4s is a lower energy level and 3d is higher. In fact, s levels should, strictly, be written first before d levels when writing electron configurations.
Is 1s22s22p63623d104s2 a pseudo noble gas electron configuration?
No, that electron configuration does not exist. After the 3p orbital fills with electrons, the next lowest energy orbital is 4s. After 4s contains 2 electrons, then 3d can accept electrons, upto 10. The element with this electron configuration is zinc, one of the transitional metals. Although 3d is full, those electrons can be 'valence' electrons and given to non-metals to form ions, such as Zn+2 or Zn+4. So 3d really acts like a 4th shell orbital and will still be quite reactive even when full. To see just how reactive these electrons are, look at the youtube videos embedded in this site: http://www.chemicool.com/elements/zinc.html.
Why scandium has valency of 3 whereas its outer shell has only two electrons?
scandium belongs to 3d series and in scandium in addition to 2 electrons in 4s one electron of 3d subshell also takes part in bonding so its valency is three despite of only two electrons in outer shell. remember valency is no. of electrons taking part in bonding
When comparing the energy of an electron in the 3d sub-level to that of an electron in the 4s sublevel of the same atom?
They are both capable of holding a maximum of 10
Why zinc is not a noble gas since its electron configuration is 3d10?
It has two valance electrons. Abbreviated electron configuration. [Ar] 3d^10 4s^2 ( energy wise that would be 4s^2 3d^10 )
What is the electron configuration of ferrous?
Fe3+=1s2 2s2 2p6 3s2 3p6 3d5You might think that it should me ...... 4s2 3d3...this is incorrect..your argument may be that....3d sub shell has more energy than 4s sub shell...& therefore,electrons from 3d,should be removed 1st.This happens when there are no electrons in shells.....when the sub shells are filled with electrons,it change.Hence,after electrons are filled in orbitals,4s electrons have more energy than 3d electrons...so, the electron config. of Fe3+=...3p6 3d5........not 4s2 3d3Here...2 electrons are removed from 4s and 1 electron is removed from 3d....therefore,it makes Fe3+ ion..
Why does an element lose 4S electrons before 3D electrons?
Because 4s is a lower energy level and 3d is higher. In fact, s levels should, strictly, be written first before d levels when writing electron configurations.
Will 3D or 4s orbitals lose electrons first?
4s electrons are lost first. The reason is because this is more energetically favored than losing d-electrons. As a result, all transition metals can bear a +2 charge. In many cases, d-orbital electrons can also be lost. Consider V+2 and V+3; the first has all of the d-orbital electrons (the 3 belonging to Vanadium) and has lost the 2 4s electrons. V+3 has lost the 2 4s electrons and 1 3d electron.
How many unpaired electrons are present in the ground state Ge atom?
There are 6 unpaired electrons in Cr because it is an exception atom when doing electron configuration. Because of the extra stability with a full subshell, one of the two electrons in the 4s orbital will move up to the 3d orbital (which originally had only 4 unpaired) to make the 3d orbital full. Now, there is one unpaired electron in the 4s orbital and 5 unpaired electrons in the 3d orbital, which adds up to 6 total.
How many unpaired electrons does K have?
There is merely one unpaired electron in Potassium. The electron configuration of potassium is [Ar]4s^1. This means that potassium has all the electrons of argon, plus one more in the 4s orbital. All the electrons of argon are paired, so the one electron in the 4s orbital is the only unpaired electron.
4s orbital is filled before 3d orbital?
The 4s orbital falls in a slightly lower energy level than the 3d orbital when it is empty so it will fill with electrons first, but when it is full of electrons it rises to be above the 3d one so that it will lose electrons first as well.
How many electron orbitals calcium have?
Zero. Calcium has two electrons in its 4s sublevel, and none in the 3d sublevel. The 3d sublevel doesn't start filling until after the 4s sublevel is filled.
Why is the electron configuration for copper 1s22s22p63s23p63d104s1 instead of 1s22s22p63s23p63d94s2?
Because a full 4s orbital is more stable than a full 3d and half full 4s. So, the last 3d electron jumps up to the 4s orbital.
An electron which is in a 3d shell spends 100 percent of its time in that 3d shell Is that true?
No, an electron in the 3d shell can move to the 4s shell very easily.
Is 1s22s22p63623d104s2 a pseudo noble gas electron configuration?
No, that electron configuration does not exist. After the 3p orbital fills with electrons, the next lowest energy orbital is 4s. After 4s contains 2 electrons, then 3d can accept electrons, upto 10. The element with this electron configuration is zinc, one of the transitional metals. Although 3d is full, those electrons can be 'valence' electrons and given to non-metals to form ions, such as Zn+2 or Zn+4. So 3d really acts like a 4th shell orbital and will still be quite reactive even when full. To see just how reactive these electrons are, look at the youtube videos embedded in this site: http://www.chemicool.com/elements/zinc.html.
