The 8085 only supports an 8 bit address bus when it comes to IO. The range of valid addresses, for IO, is 0 to 255.
RIM, SIM, RST, to name three.
No. The 8086 has instructions not present in the 8085. The 8086 was marketed as "source compatible" with the 8085, meaning that there was a translator program which could convert assembly language code for the 8085 into assembly language code for the 8086. However, this does not mean that the compiled 8086 assembly code would then run on an 8085; among other things, the 8086 was a true 16-bit processor, as opposed to the 8085 which was an 8-bit processor that supported a few 16-bit operations.
8085 is a microprocessor designed by Intel
In the number 5000, there is only one "1" present, which is in the thousands place. The digit "1" appears only once in the entire number.
The 8085 was replaced with the 8086/8088. As such, there is no 16 bit version of the 8085.
The 8085 has a single +5V power supplyThe 8085 has a multiplexed low order address busThe 8085 has extra single pin interrupts, TRAP, RST7.5, RST6.5, and RST5.5The 8085 has serial I/O pins SID and SODThe 8085 has maskable interrupts and the RIM/SIM instructionThe 8085 includes the functionality of the 8224 clock genereator and 8228 system controllerThe 8085 added several 16 bit operations
5000
The 8085 is not pipelined.
The 8085 was introduced by Intel in 1977.
The '8085' in the 8085 microprocessor is the designation given to the microprocessor by Intel. The '5' means it is a single power supply (5 volt) version of the 8080, with enhancements.
There are 74 instructions in the 8085 microprocessor.
Yes because 8085/77 = 105