whose resistance is zero.but it is practically not possible. there is something resistance present in the wire
Capacitors and Inductors theoretically consume no power. In real life, they only consume power because they have an internal resistance.
The power consumed by an inductor is not zero since it's resistance is not zero either. The power consumed is just too minimal that it can be ignored. What the inductor does is, during one half of the Current's sinusoidal waveform, it stores energy in the form of magnetic flux. During the next half,it discharges the stored energy into the circuit by losing the magnetic field. Hence,they say it doesn't consume power. If the inductor's resistance was significant then you will see that it will consume power. Resistance and Reactive resistance are two different things.
The current through a pure, or ideal, inductor having zero resistance, would lag the voltage with a phase angle of 90 degrees. The inductive reactance of a 1 Henry inductor at 60 hz is about 380 ohms. XL = 2 * pi * f * L so 200 volts at 380 ohms is about 0.53 amps and the power drawn, using the basic Power equation: power = volts * amps, would be about 105 vars. Var is the correct term for volts times amps, or volt-amp-reactive, where we consider the phase angle to be 90 degrees.
Yes if you are referring to no real power, no if you are saying no power (real or reactive). You could have 100A flow from a capacitor bank or inductor bank, which should consume no real power, but provide voltage support / pull down when on line by introducing reactive power to the system.
To improve the power factor
If it's a pure inductor, no power consumption. However it must be wound using unobtanium wire which has zero resistance, and the core must be vacuum. Air is nearly lossless.
Capacitors and Inductors theoretically consume no power. In real life, they only consume power because they have an internal resistance.
An inductor is a device which stores energy as a magnetic energy.... Ideal inductor have no resistance.....so there is no power loss.... power loss = (I*I)*R
Pure inductors consume and produce power, just like other reactive devices. The difference is that the current is not in phase with the voltage, resulting in the waveform of the power being oscillating about zero, with a net mean power of zero. In this "pure" case, the power factor is zero, but that does not mean there is no power - its just that the power "reading" is unsophisticated and not compensating for power factor.
Angle between v and i is 90 deg so, cos 90 = 0 Same for pure capacitor
The power consumed by an inductor is not zero since it's resistance is not zero either. The power consumed is just too minimal that it can be ignored. What the inductor does is, during one half of the Current's sinusoidal waveform, it stores energy in the form of magnetic flux. During the next half,it discharges the stored energy into the circuit by losing the magnetic field. Hence,they say it doesn't consume power. If the inductor's resistance was significant then you will see that it will consume power. Resistance and Reactive resistance are two different things.
In an ideal inductor, no, there is no voltage induced across an inductor unless the current in the inductor is changing. However, since there are no ideal inductors nor power supplies, eventually an inductor will draw a constant current, i.e. the limit of the power supply; and, since no inductor has zero ohms at equilibrium, that current will translate to voltage.
The current through a pure, or ideal, inductor having zero resistance, would lag the voltage with a phase angle of 90 degrees. The inductive reactance of a 1 Henry inductor at 60 hz is about 380 ohms. XL = 2 * pi * f * L so 200 volts at 380 ohms is about 0.53 amps and the power drawn, using the basic Power equation: power = volts * amps, would be about 105 vars. Var is the correct term for volts times amps, or volt-amp-reactive, where we consider the phase angle to be 90 degrees.
In an AC circuit energy flows into an inductor in one quarter-cycle and flows out on the next. Ditto for a capacitor. Therefore over a cycle, no net power or energy is consumed in a pure capacitor or inductor.Another Answer'Power' is the rate at which energy is transferred. In the case of 'pure' inductance or capacitance, energy flows from the supply to the device during the first quarter-cycle of current, where it is temporarily stored within the magnetic (inductors) or electric (capacitors) field, only to be returned to the supply during the following quarter-cycle. You could describe this action as 'energy sloshing back and forth between the supply and the device'. The rate at which this energy transfer takes place is called 'reactive power' and is expressed in 'reactive volt amperes'. None of this energy is lost or, to use your expression, 'consumed'.'True power', expressed in watts, is the rate at which energy is expended -i.e. energy taken from the supply and then dispersed through work (e.g. by motors) or heat transfer (losses). This does NOT occur in purely-inductive or in purely-capacitive loads. So, in answer to your question, 'power' (in the sense of 'true power') is NOT 'consumed' by a pure inductor or capacitor (remember, technically, it's energy that gets consumed, not power -power is simply a rate).You should bear in mind, however, that there is no such thing as a 'pure inductor' or 'pure capacitor' as each will exhibit some degree of resistance. Resistance results in the expenditure of energy, the rate at which it occurs being 'true power'. So 'real' inductors and capacitors combine 'reactive power' with 'true power', the vector-sum of which we call 'apparent power', expressed in volt amperes.
Yes if you are referring to no real power, no if you are saying no power (real or reactive). You could have 100A flow from a capacitor bank or inductor bank, which should consume no real power, but provide voltage support / pull down when on line by introducing reactive power to the system.
To improve the power factor
pi filter is best using inductor and capacitor.