An inductor is a device which stores energy as a magnetic energy.... Ideal inductor have no resistance.....so there is no power loss.... power loss = (I*I)*R
inductance
whose resistance=0,inductance=0
super conductivity
The copper loss measurement must be replaced by load loss measurement in accordance to IEEE C57.12.00 and C57.12.90. Since that a power transformer is conected typically with one winding short circuited and the rated current is supplied in the other (typically high voltage side), the transformer is like an almost pure inductance load, with a lag power factor between 0.01 and 0.03. Therefore a capacitive reactive power is required to compensate this almost pure inductive reactive power demanded by the test. If you require further information please let me know.
No, because it is not loss - inductance by definition will cause reactive power which can be compensated for using capacitor banks (one example). I^2 * R losses (power loss through the cable) takes into account the resistance of the line.
When voltage and current waveforms are out of synch the power factor is reduced. In a pure resistance load the PF is 1. When inductance and capacitance is involved the PF is from 0 to 1.
90 degrees
The unit of power measured is watt, irrespective of resistance, capacitance or inductance of the circuit.
A coil of wire acts as an inductor; it will have a very small resistance, and a relatively large inductance. Power factor is effectively the resistance divided by the impedance (made up of resistance and inductance), so the larger the inductance relative to the resistance, the lower the power factor will be.
inductance and capictances, lowpower factor
Transformer Inductance?
The coil consists of inductance. Due to inductance the current lags the voltage. So, the power factor is lagging.