because of the residual magnetic flux that exists in the motor initially due to the poles
because of the residual magnetic flux that exists in the motor initially due to the poles
Motor started will have overloads the contactor connect es line voltage.
the excitation voltage applied the power input to the prime mover
Servo motors are geared DC motors with the closed-loop circuitry incorporated within them. The basic configuration of a servo motor composed of a DC motor, gearbox, potentiometer and control circuit.DC motor is used to move a gearbox with a large reduction ratio. The final shaft imposes a force on the external load and simultaneously acts on the axis of the feedback potentiometer. So, the potentiometer senses the position of the axis and sends a corresponding voltage to an operational amplifier. This voltage compared to the input voltage, that determines the desired position of the shaft, producing a voltage in the output of the comparator. This voltage powers the motor such that the shaft moves in the necessary direction to align with the angle that corresponds to the voltage applied to the input.
You can use a DC motor speed controller with pulse width modulation (PWM) to regulate the voltage supplied to the motor, thus slowing it down. By adjusting the duty cycle of the PWM signal, you can effectively control the speed of the motor while maintaining a constant voltage input. Another option is to use a resistor in series with the motor to reduce the voltage, but this method is less efficient and may cause power loss and heating issues.
Frequency drives are an adjustable-speed drive used for electro-mechanical drive systems. They control the motor speed and torque by varying motor input frequency and voltage.
You can use a voltage regulator IC/transistor that can take any input voltage (to a point) and spit out whatever voltage you want, depending on your application (in this case 380 volts) then be sure you build a regulator with the correct IC/transistor. Hope this helps!
Open loop control systems are one in which Output have no effect on input. Toaster,Washing machine and a Dc motor are the examples. Consider an example of a dc motor, Due to voltage input it rotates a Shaft what happen if the load on shaft increases ???do you get the same output on same input??not possible because there is no such mechanism involved that will tell the motor to increase its input...that is no feedback mechanism involved in open loop system..thats why you will get a decrease in Output.
the voltage tolerance of a standard electric motor is
You can't. You must supply the motor with it's required voltage. If it's a dual voltage motor, follow the wiring schematic on the motor nameplate to switch from low to high voltage.
From my understanding of electronics: The input voltage -- generally the higher the voltage, the faster the motor will go. Of course, this will shorten the life of your motor. The motor itself -- Different motors are designed for different applications (i.e. high torque, high speed, etc.) Gearbox (a.k.a. transmission) -- Can increase the speed of a motor with a sacrifice of torque or vice versa.
250 kW= 250,000 watts1 horsepower=746 watts (The motor is approx. 335 horsepower. (just FYI))The Ohm's Law formula for this is:P(Power in watts)=I(Current in amps) x E(Voltage)Since the voltage is unknown, I will give you different options based on input voltage.I will assume three phase power for a motor this size.So, back to the formula:250,000=I x ELet's assume voltage (E) to be 480v:250,000=I x 480I=520 ampsFor a voltage of 208 (much less likely for this size motor):250,000=I x 208I=1201 ampsThese are 'running' currents only. The amount of starting current will be much, much higher, but only for a brief period.AnswerThe above answer assumes that the motor's input power is 250 kW. But this is not the case.The power of a motor is always expressed in terms of its output power, not its input power! In North America, this is expressed in horse power, whereas everywhere else it's expressed in watts. So, to determine the current drawn by the motor, you have to start by determining its input power (input power is output power times efficiency); if you don't have a means of determining the motor's efficiency, then you cannot really find out its input power, in which case, you cannot find its current.