Because hydrogen bonds between the OH components alter the vibration frequency slightly. The broad band is the result of many such interactions between molecules in the sample. For CO components there is no hydrogen bonding hence the absorption is sharp.
CO
first off you wrote down the equation wrong its Co(OH)3 and its pronounced cobalt three hydroxide additionally from looking at the formula you know that cobalt has a +3 charge
The chemical reaction is: 4 H3BO3 + 2 NaOH = Na2B4O7 + 7 H2O
A specific answer would require knowledge of the exact chemicals involved. However, the principle is that each functional group produces an absorbtion at a different wave number. For instance, if you oxidised an alcohol to a ketone, you'd expect the broad OH stretch at the left of the plot to be replaced by a sharp, narrow peak nearer the middle.
Two laboratory methods are:2 NH4Cl + 2 CaO = CaCl2 + Ca(OH)2 + 2 NH3(NH2)CO + Ca(OH)2 = CaCO3 + 2 NH3
Oh yes. The red tail, red shouldered, Cooper's, sharp shinned, kestrel, and broad winged hawks are all found in Connecticut.
The subscript for cobalt II hydroxide is Co(OH)2
CO
O (not Oh) - rin - oh - co river
No you will have to take the test in CO.
carboxly
Bill Sharp was born January 18, 1950, in Lima, OH, USA.
Wadsworth DMV Location123 Broad StreetWadsworth, OH 44281
oh yea
uh oh see a doctor
YES ------COOH is a carboxylic acid group
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