The products of propanol combustion are water and carbon dioxide.
first off you wrote down the equation wrong its Co(OH)3 and its pronounced cobalt three hydroxide additionally from looking at the formula you know that cobalt has a +3 charge
Internal combustion engines usually use some kind of hydrocarbon fuel (gasoline for example). The fuel is burned together with the oxidizer (atmospheric air in most cases with the exception of rocket engines). The result of the chemical reaction between the hydrocarbon fuel and air is H2O, CO2 and, in smaller quantities (depending on the proportions in which the fuel and air are mixed into the combustion chamber), some radicals like CO, OH, O, H maybe even C solid particles (also known as soot). The process is not as simple as it is taught in high school chemistry as there's no single reaction leading from reactants to final products. There are many reactions leading from the decomposition of the gasoline and air molecules to the formation of the final products (all of this reactions form the reaction mechanism). You can read more about reaction mechanisms in the related link.
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The chemical reaction is: 4 H3BO3 + 2 NaOH = Na2B4O7 + 7 H2O
2C2H3OH + 5O2 --> 4CO2 + 4H2O The equation as written appears to be complete combustion, but in reality it probably would not be complete combustion. Usually combustion is incomplete, producing other products such as carbon monoxide and pure carbon (soot).
The products of propanol combustion are water and carbon dioxide.
Saponification is the hydrolysis of fat in presence of caustic soda (NaOH), the products are Soap and Glycerin CH2-CO-R1 CH2-OH R1-COONa | | CH-CO-R2 + 3NaOH --------> CH-OH + R2-COONa | | CH2-CO-R3 CH2-OH R3-COONa (Fat) (Glycerin) (Soap)
The subscript for cobalt II hydroxide is Co(OH)2
O (not Oh) - rin - oh - co river
No you will have to take the test in CO.
All organic compounds containing only carbon and hydrogen (such as ethanol) always form carbon dioxide and water vapour on complete combustion in open air.
carboxly
CO2 + Ca(OH)2 write a balanced equation for the combustion of benzene (C6H6)and find the mass of CO2 produced from the complete combustion of 25g benzene
oh yea
YES ------COOH is a carboxylic acid group
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