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Why as the water falls its speed increases and the area of cross section decreases?
Wiki User
∙ 12y ago
It is explained by mass conservation, and water being an incompressible fluid.
Imagine water going through a pipe with varying inside diameters Di's. Water will
flow the fastest in the pipe section with the smallest diameter, and will flow the
slowest in the widest section of the pipe.
The product of the volumetric average velocity of the water flow v, times the
cross section area A, is equal to the volumetric flow rate (vol/time) G.
G = v∙A
If you have a constant volumetric flow rate, if the area reduces to half, the velocity doubles.
By the way, if you multiply the volumetric flow rate G by the liquid density ρ, you
get the mass flow rate Q, (mass/time). Q = G∙ρ = ρ∙v∙A
Wiki User
∙ 12y ago
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