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Atoms both give up and receive electrons in the bonding proccess. The determining factor is simple how many electrons said atom has in it's outer shell. All atoms strive to be bear a full outer shell or a stable octet. Electrons arange themselves into shells around an atom, 2 in the first, 8 in the next two. If an atom has two electrons in its second shell it is simpler for it to loose two electrons to acheive a full shell then to gain six. Conversly if it has seven electrons in its third shell it will exept one more to fill its shell. i hope this helps and if anyone has a more correct response please be kind.

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Q: Why atom tend to give up electrons during the process of chemical combination possesses?
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