In the case of chromium (Cr), the electron configuration of 3d54s1 is more stable than 3d44s2. A half-filled sublevel is more stable than a sublevel that is less than half full. In the case of copper (Cu), the electron configuration of 3d104s1 is more stable than 3d94s2, again because a full sublevel and a half-filled sublevel is more stable.
Because a full 4s orbital is more stable than a full 3d and half full 4s. So, the last 3d electron jumps up to the 4s orbital.
3d
The 4s orbital falls in a slightly lower energy level than the 3d orbital when it is empty so it will fill with electrons first, but when it is full of electrons it rises to be above the 3d one so that it will lose electrons first as well.
4s will fill first because it is at a lower energy level than the 3d level.
There is merely one unpaired electron in Potassium. The electron configuration of potassium is [Ar]4s^1. This means that potassium has all the electrons of argon, plus one more in the 4s orbital. All the electrons of argon are paired, so the one electron in the 4s orbital is the only unpaired electron.
Because a full 4s orbital is more stable than a full 3d and half full 4s. So, the last 3d electron jumps up to the 4s orbital.
three, as follows:the 4s orbital is full with 2 electronsthe 4p orbitals contain only 1 electron (of a possible 6)
the 4s orbital is lower in energy than the 3d orbitals
The electrons fill in the lowest energy orbital that is available. Electrons in the 4s orbital have a lower energy level than electrons in the 3p orbital, so the 4s orbitals are filled with electrons first.
3d
4s-orbital will be filled prior to 3d-orbital.ORBITALnl(n+l)4s404+0 = 43d323+2 = 5Since 4s-orbital has least value of (n+l), therefore ,it will occupy electrons before3d-orbital.The order of increasing of energy of orbitals can be calc. from(n+l) rule or 'Bohr bury rule' According to this rule, the value of n+l is the energy of the orbital and such on orbital will be filled up first. e.g. 4s orbital having lower value of(n+l) has lower energy than 3d orbital and hence 4s orbital is filled up first. For 4s orbital, n+l=4+0=4 For 3d orbital, n+l=3+2=5,therefore 4s orbital will be filled first.
The 4s orbital falls in a slightly lower energy level than the 3d orbital when it is empty so it will fill with electrons first, but when it is full of electrons it rises to be above the 3d one so that it will lose electrons first as well.
4s will fill first because it is at a lower energy level than the 3d level.
The 3d sublevel is not filled until after the 4s sublevel, because the 3d sublevel has more energy than the 4s sublevel, and less energy than the 4p sublevel.
because its energy level is lower
There is merely one unpaired electron in Potassium. The electron configuration of potassium is [Ar]4s^1. This means that potassium has all the electrons of argon, plus one more in the 4s orbital. All the electrons of argon are paired, so the one electron in the 4s orbital is the only unpaired electron.
There are 6 unpaired electrons in Cr because it is an exception atom when doing electron configuration. Because of the extra stability with a full subshell, one of the two electrons in the 4s orbital will move up to the 3d orbital (which originally had only 4 unpaired) to make the 3d orbital full. Now, there is one unpaired electron in the 4s orbital and 5 unpaired electrons in the 3d orbital, which adds up to 6 total.