Want this question answered?
because they are stable
why do alkali metels not show +2 oxidation state
Never. iron shows either +2 or +3 oxidation state but in Fe3O4 its oxidation state is seems to +4 but it is actually mixture of one moles FeO and one mole Fe2O3 , (FeO.Fe2O3 = Fe3O4).
Ruthenium and Osmium both show the oxidation state of +8, which is highest known for any single metal ion.
Because they have only one electron in their valency shell. The second oxidation state would require the atom to lose an electron from its penultimate shell which is full.
because they are stable
why do alkali metels not show +2 oxidation state
If you are talking about the elements then they are two different elements with different atomic no. and properties. On the other hand if you are talking about the 2 groups in the F block then there are 3 major differences: 1. Except for Promethium lanthanoids are not radioactive while all Actinoids are 2. Oxidation state is usually +3 for Lanthanoids and they also show +2 & +4 while Actinoides show +4,+5,+6,+7 Oxidation States 3. The magnetic property of Actinoids are more complex than Lanthanoids
When halogens bind to more electropositive elements (compared it itself), they show -1 oxidation state. When halogens bind to more electronegative elements (compared it itself), they show +1 oxidation state.
Due to the comparable energies of ns and the (n-1)d orbitals, the d-electrons also take part in the reactions.
It is rarely, but manganese can show the valence 5+.
Never. iron shows either +2 or +3 oxidation state but in Fe3O4 its oxidation state is seems to +4 but it is actually mixture of one moles FeO and one mole Fe2O3 , (FeO.Fe2O3 = Fe3O4).
All are radioactive and all of them can show the oxidation state of +3
Ruthenium and Osmium both show the oxidation state of +8, which is highest known for any single metal ion.
Because they have only one electron in their valency shell. The second oxidation state would require the atom to lose an electron from its penultimate shell which is full.
They show the oxidation an reduction halves of a reaction
Transition metals can move electrons between the outer shell and the d d orbital. For example, copper can either lose its 2 s electrons or move one of those s electrons into d orbital, which is one electron short of being full.