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What is the molarity of a solution made by dissolving 4.88 g of KCl in 423 mL of solution?
Need mole KCl first. 4.88 grams KCl (1 mole KCl/74.55 grams) = 0.06546 moles KCl =======================now, Molarity = moles of solute/Liters of solution ( 423 ml = 0.423 Liters ) Molarity = 0.06546 moles KCl/0.423 Liters = 0.155 M KCl ------------------
How many moles of KCl are contained in 0.635L of 2.2M KCl?
moles KCl = ( M solution ) ( V solution in L )moles KCl = ( 2.2 mol KCl / L solution ) ( 0.635 L of solution )moles KCl = 1.397 moles KCl
How many moles of KCl are needed to prepare 1.00 L of a 1.0M KCl solution?
M= moles in solution/liters so plug in what you know 3.0M of KCl solution = moles in solution/ 2.0L multiply both sides by 2.0L moles solute = 1.5 moles KCl so you need 1.5 moles KCl to prepare the solution
How many moles of KCl are contained in 1.7L of a 0.83M KCl solution?
moles KCL = ( M solution ) ( L of solution )moles KCl = ( 0.83 mol KCl / L ) ( 1.7 L ) = 1.41 moles KCl
How many moles of KCI would be dissolved in 4 liters of water to make a 2 Molar solution?
We need 8 moles potassium chloride.
How many g of KCl do you need to make 2.5 L of a 10 weight volume solution?
For a 10 % solution you need 250 g KCl.
What volume of 12.0M KCl is required to make 300.0 ml of 0.50 M KCl?
In order to make 300.0 ml of 0.50 M KCl you need 0.300 L x 0.50 M = 0.150 moles KCl. To make 0.150 moles of 12.0 M KCl you need 0.150 moles / 12.0 M = 0.0125 L = 12.5 ml.
What is the molarity of a solution made by dissolving 4.88 g of KCl in 423 mL of solution?
Need mole KCl first. 4.88 grams KCl (1 mole KCl/74.55 grams) = 0.06546 moles KCl =======================now, Molarity = moles of solute/Liters of solution ( 423 ml = 0.423 Liters ) Molarity = 0.06546 moles KCl/0.423 Liters = 0.155 M KCl ------------------
How many moles of KCl are contained in 0.635L of 2.2M KCl?
moles KCl = ( M solution ) ( V solution in L )moles KCl = ( 2.2 mol KCl / L solution ) ( 0.635 L of solution )moles KCl = 1.397 moles KCl
What is the mole ratio for KCl?
KCl
What is KCl?
KCL is Potassium Chloride.
How many moles of KCl are needed to prepare 1.00 L of a 1.0M KCl solution?
M= moles in solution/liters so plug in what you know 3.0M of KCl solution = moles in solution/ 2.0L multiply both sides by 2.0L moles solute = 1.5 moles KCl so you need 1.5 moles KCl to prepare the solution
How many ml of 0.25M KCl are needed to provide 0.012 moles of KCl?
0.012mol KCl x (1L/0.25mol KCl) x (1000ml/1L) = 48 mL KCl
How many moles of KCl are contained in 1.7L of a 0.83M KCl solution?
moles KCL = ( M solution ) ( L of solution )moles KCl = ( 0.83 mol KCl / L ) ( 1.7 L ) = 1.41 moles KCl
What volume of 0.060 M KCl solution contains 2.39g of KCl?
MW KCl = 74.6 g/mol2.39 gKCl * (1 mol KCL/74.6 g KCl)*(1 L solution/0.06 mol KCL) = 0.534 L
What is the compound for KCl?
I'm guessing you meant KCl or potassium chloride.
How many moles of KCI would be dissolved in 4 liters of water to make a 2 Molar solution?
We need 8 moles potassium chloride.
