It's a simple acid-base reaction, your acid being your 2HCl and your base being CuO. Acid-base reactions form water, leaving behind a salt (CuCl2).
The product is copper ii chloride alongwith water, CuO + 2HCl = CuCl2 + H2O
CuO + 2HCl --> CuCl2 + H2O
copper+hydrocloric acid=Copper chloride+hydrogen Cu+2HCl=CuCl2+H2 The first part of the salt is from the acid The second part is from the alkali, metal, or metal carbonate hydrochloric acid gives chloride sulfuric acid give sulfate nitric acid gives nitrate
CuO + H2 ------> Cu + H2O. You shouldn't say "plus" for the reactions, it has to be the arrow as the arrow symbolises lots of complicated reactions, making it different to adding them together.
No reaction will be observed. Copper is too unreactive and cannot displace hydrogen from hydrochloric acid. Only reactive metals (above hydrogen in the reactivity series) will react with dilute acids.
CuO + 2HCL - CuCl2 + H2O
The product is copper ii chloride alongwith water, CuO + 2HCl = CuCl2 + H2O
CuO + 2HCl --> CuCl2 + H2O This equation is a double displacement; because Cu (Copper) has pushed out O (oxygen), so that Cu can be with Cl (chlorine). Also, H (Hydrogen) has pushed out Cl to be with O. Both elements have pushed out their partner, therefore a double displacement.
CuO + 2HCl --> CuCl2 + H2O
CuO + 2 HCl -> CuCl2 + H2O Please see the link.
This equation is 2 HCl + CuO -> CuCl2 + H2O.
copper+hydrocloric acid=Copper chloride+hydrogen Cu+2HCl=CuCl2+H2 The first part of the salt is from the acid The second part is from the alkali, metal, or metal carbonate hydrochloric acid gives chloride sulfuric acid give sulfate nitric acid gives nitrate
CuO + H2 ------> Cu + H2O. You shouldn't say "plus" for the reactions, it has to be the arrow as the arrow symbolises lots of complicated reactions, making it different to adding them together.
The HCl will react with the CuO in a double replacement reaction given by the equation: 2HCl + CuO --> CuCl2 + H2O. Copper(II) chloride is water soluble, so it will clean right out.
CuO(s) + 2HCl(aq) --> CuCl2(aq) + H2O(l) Copper oxide + Hydrochloric Acid --> Copper Chloride + Water
No reaction will be observed. Copper is too unreactive and cannot displace hydrogen from hydrochloric acid. Only reactive metals (above hydrogen in the reactivity series) will react with dilute acids.
Cu(CO3)2 + 2 HCl ---------- CuCl2 + 2 CO2 + H2O