copper+hydrocloric acid=Copper chloride+hydrogen
Cu+2HCl=CuCl2+H2
The first part of the salt is from the acid
The second part is from the alkali, metal, or metal carbonate
hydrochloric acid gives chloride
sulfuric acid give sulfate
nitric acid gives nitrate
The balanced equation for the decomposition of copper (II) hydroxide is: Cu(OH)2(s) → CuO(s) + H2O(g)
Balanced equation: CuO + 2HCl --> CuCl2 + H2O Word equation: One mole of copper (II) oxide plus two moles of hydrochloric acid produces (or yields) one mole of copper (II) chloride plus one mole of water.
The balanced chemical equation for the reaction between copper carbonate (CuCO3) and hydrochloric acid (HCl) is: CuCO3 + 2HCl → CuCl2 + H2O + CO2. This equation shows that copper carbonate reacts with hydrochloric acid to form copper (II) chloride, water, and carbon dioxide.
Cu(OH)2+2HCl=CuCl2+2H2O
When copper hydroxide reacts with hydrochloric acid, it forms copper chloride and water. This reaction involves the exchange of ions between the copper hydroxide and the hydrochloric acid.
The balanced equation for the decomposition of copper (II) hydroxide is: Cu(OH)2(s) → CuO(s) + H2O(g)
Balanced equation: CuO + 2HCl --> CuCl2 + H2O Word equation: One mole of copper (II) oxide plus two moles of hydrochloric acid produces (or yields) one mole of copper (II) chloride plus one mole of water.
The balanced chemical equation for the reaction between copper carbonate (CuCO3) and hydrochloric acid (HCl) is: CuCO3 + 2HCl → CuCl2 + H2O + CO2. This equation shows that copper carbonate reacts with hydrochloric acid to form copper (II) chloride, water, and carbon dioxide.
Cu(OH)2+2HCl=CuCl2+2H2O
When copper hydroxide reacts with hydrochloric acid, it forms copper chloride and water. This reaction involves the exchange of ions between the copper hydroxide and the hydrochloric acid.
The chemical equation is:Cu(OH)2 + 2 HCl = CuCl2 + 2 H2O
The balanced equation for the reaction between copper(II) hydroxide (Cu(OH)2) and sulfuric acid (H2SO4) is Cu(OH)2 + H2SO4 → CuSO4 + 2H2O.
This equation is 2 HCl + CuO -> CuCl2 + H2O.
2HCL+CuCO3---> CuCl2_H2O_CO2
copper bromide + sodium Hydroxide = Copper Hydroxide + Sodium Bromide CuBr2 + 2NaOH = Cu (OH)2 + 2NaBr
The balanced chemical equation for the reaction between sodium hydroxide and copper(III) chloride is: 2NaOH + 3CuCl3 → 3Cu(OH)3 + 6NaCl This equation shows that two moles of sodium hydroxide react with three moles of copper(III) chloride to produce three moles of copper(III) hydroxide and six moles of sodium chloride.
Copper(II) hydroxide, when heated, decomposes to form copper(II) oxide and water. The balanced equation for this reaction is: 2Cu(OH)2(s) -> 2CuO(s) + H2O(g)