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(ALL HAIL LORD LOG)
super log smashes everyone who gets in his way...
(mostly 'EMOS' )
And for u EMOS u will be so scared u will scream off ur guts (and run)
THANK YOU!!!!!
O/__\O
Wiki User
∙ 8y ago
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How do you get a diabetic log book?
Many companies that offer blood glucose machines also offer diabetic log books. Log into their website and see....doesn't hurt to ask.
What is the answer to log x6?
log(x6) = log(x) + log(6) = 0.7782*log(x) log(x6) = 6*log(x)
What is the name of the brains circulatory system?
tom dunsdons dad and mum log log log log log log log in my buttt
Will heat from your gas log fireplace damage an LCD flat screen hung over the mantle?
If the heat from your fireplace is being blown forward, then it shouldn't hurt your TV.
The log of a quotient is the log of the numerator divided by the log of the denominator?
Not quite. The log(x/y) = log(x) - log(y) In words, this reads "The log of a quotient is the difference of the log of the numerator and the log of the denominator."
The log of a quotient is the log of a numerator divided by the log of the denominator?
No. The log of a quotient is the log of a denominator subtracted from the log of the numerator.
If log a equals x and log b equals y what is log?
"Log" is not a normal variable, it stands for the logarithm function.log (a.b)=log a+log blog(a/b)=log a-log blog (a)^n= n log a
Is it log on to or log onto?
log on to
If 3 log x - 2 log y?
1
Log x - log 6 equals log 15?
log(x) - log(6) = log(15)Add log(6) to each side:log(x) = log(15) + log(6) = log(15 times 6)x = 15 times 6x = 90
Is log 5 equivalent to log 5-log 20?
No. log 20 is a positive number , so it you subtract it from log 5 you get less than log 5. However, log10 5 = 1 - log102 = 2- log1020 . or log 5 - log 20 = log 5 - log 4*5 = log 5 - (log 5 + log 4) = log 5 - log 5 - log 4 = - log 4 But we do not need to do all of these computations, because log 5 is different from log 5 - log 20 by the law of the equality that says two equals remain equal if and only if we subtract (in our case) the same thing from them.
How do you solve for a power in a math problem?
You have to use logarithms (logs).Here are a few handy tools:If [ C = D ], then [ log(C) = log(D) ]log(AB) = log(A) + log(B)log(A/B) = log(A) - log(B)log(Np) = p times log(N)
