Want this question answered?
Light energy W= qV=hf , then light frequency or color depends on energy qV here V is volts. Thus, f = qV/h = (240Thz/volt) V indicating infrared frequency/volt.
Divide the Mega Electron Volts by h in electron volts h=4.16E-15 evseconds. ( h=2/3E-33 Js x6.25 ev/J =4.16E-15 evs. Frequency, f=Mev/4.16E-15s.
The fusion frequency is the minimum stimulus required to elicit tetanus in a muscle. For example, the fusion frequency can be given in terms of volts (V), or it can be given in terms of whatever units by which the applied stimuli are being measured.
The electric potential difference is measured in volts. The amount of volts will depend on what kind of plates and the solution which the plates have been put in to.
On this calculation I am assuming that the light bulb is using a 120 volt source. Watts = Amps x Volts. Amps = Watts/Volts, 40/120 = .33 amps. R = Volts/Amps, 120/.33 = 363.6 ohms resistance in the 40 watt light bulb.
Light energy W= qV=hf , then light frequency or color depends on energy qV here V is volts. Thus, f = qV/h = (240Thz/volt) V indicating infrared frequency/volt.
the watts in the lamp and the volts behind the light
Basically, "frequency" applies to AC, not to DC. If you want to assign it a frequency, the frequency is zero. The amount of volts is not relevant.
There are no volts in a light. A light consumes power.
A: Take 115 volts and multiply by 2.82. The frequency does not matter but he voltage does
The mains voltage is 230 volts, and the frequency is 50Hz.
6 volts
As many as you want. But where do you find 640 volts RMS?
Onions don't have volts.
Divide the Mega Electron Volts by h in electron volts h=4.16E-15 evseconds. ( h=2/3E-33 Js x6.25 ev/J =4.16E-15 evs. Frequency, f=Mev/4.16E-15s.
A light bulb connected between to wires, each having 300 volts to ground that are in phase, will not light, because there is no differential voltage available to do any work. If each wire has 300 volts to ground and are out of phase (600 volts between them) the light bulb will be lit, if it is rated at least for 600 volts, otherwise it will burn out.
No, the voltage is 220 volts at a frequency of 50 Hertz.