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Utility voltage is 115 volts at a frequency of 60 Hz what is the peak to peak?
Wiki User
∙ 13y ago
A: Take 115 volts and multiply by 2.82. The frequency does not matter but he voltage does
Wiki User
∙ 13y ago
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What is the difference of peak and rms value?
RMS stands for "Root of the Means Squared", and is a mathematical method of defining the "operating" voltage of a sine wave power source. Typical home lighting and outlet voltage presently is 120 VAC (volts alternating current), 60 Hz. (Hertz, formerly referred to as "cycles per second".) But the PEAK voltage is the absolute maximum voltage at the "peak" of each sine wave of voltage. Mathematically, the "Peak" voltage is 1.414 (which is the square root of the number 2) times the RMS voltage, and conversely, the RMS voltage is 0.707 times the PEAK voltage.
What is the relationship between RMS and peak voltage for a square waveform?
RMS and peak voltage for a square waveform are the same. There is a small caveat, and that is that you'd have to have a "perfect" square wave with a rise time of zero. Let's have a look. If we have a perfect square wave, it has a positive peak and a negative peak (naturally). And if the transition from one peak to the other can be made in zero time, then the voltage of the waveform will always be at the positive or the negative peak. That means it will always be at its maximum, and the effective value (which is what RMS or root mean square is - it's the DC equivalent or the "area under the curve of the waveform") will be exactly what the peak value is. It's a slam dunk. If we have a (perfect) square wave of 100 volts peak, it will always be at positive or negative 100 volts. As RMS is the DC equivalent, or is the "heating value for a purely resistive load" on the voltage source, the voltage will always be 100 volts (either + or -), and the resistive load will always be driven by 100 volts. Piece of cake.
What is the peak inverse voltage rating of diode in bridge rectifier?
2x the peak supply voltage!
How you can prove the Peak voltage?
Use an oscilloscope. That shows the voltage waveform and you can read the peak value.
Will AC voltage or DC voltage have higher illumination intensity when provided at the same voltage?
Is this a trick question? It could be. Let's look at AC and DC and see what's up. We'll start with DC. DC is direct current. The voltage of "regular" DC is a fixed value. Like in a car, the battery is about 12 volts. (It's actually a bit higher, but work with me here.) It's a nice, constant 12 volts all the time. The headlights experience a constant 12 volts when they are on. What about AC? Alternating current, or AC, is based on a voltage source that has a changing polarity. For a while it's one way, and then for a while it's the reverse. Also, the voltage isn't constant and then suddenly changing polarity. If we look at the voltage on an AC line, at a certain instant, the voltage is zero. It then rises up over a short time to some maximum value and then decreases to zero again. Then the polarity changes and the voltage goes to some maximum negative value before returning to zero. We usually think of a sine wave, and that's pretty correct. This is how the voltage is actually generated in a generator. It spins, and the voltage output follows a sine wave. Cool so far? Good. Let's jump. With the AC voltage rising to some maximum value, what is that maximum? And since it rises to the value over a short period of time rather than just jumping straight up there, don't we have to "average out" the voltage over the time it takes for it to get to the maximum? And then "average it out" for the back half of that change as it decreases to zero? Yes, we do. And what we end up with is an "effective" voltage, or a "DC equivalent" voltage. In U.S. houses, the 120 volts AC (again, work with me here) is actually the DC equivalent voltage of the AC sine wave. The sine wave actually has a peak at about 170 volts. We could say that a given sine wave has a peak voltage of 170 volts. Or, since it goes negative as much as it goes positive, the total voltage change from the positive peak to the negative peak is twice the peak voltage, or 340 volts peak to peak. But we like to use the "average" or (mathematically) the root mean square voltage, which is the DC equivalent voltage to measure AC. So if an incandescent reading lamp on an end table in a house is plugged into a 120 volt wall outlet, it will have the same brightness as if the lamp was hooked up to a 120 volt DC battery. The effective voltages will be the same because the AC voltage is actually based on the DC equivalent voltage.
If a building has only 101 volts at the outlets but should be at least 110 volts what could be the problem?
First check voltage at the main and make sure you have 220 volts coming in. Check the voltage at both peak and off peak hours. If you find low voltage at the main lugs contact you local utility provider.
What is the peak to peak voltage for the AC line voltage in normal outlets of your house?
Peak - neutral for 120 volts RMS is 169 volts, or 120 * sqrt(2) Peak to peak will be 2 x this value, or 339 volts.
What is average voltage?
Another name for average voltage is the RMS (Root Mean Square). This is a voltage derived from the peak to peak voltage multiplied by .707. If the peak to peak voltage is 170 volts then the average voltage (RMS) would be 170 x .707 = 120 volts.
What is the effective voltage for a peak voltage of 311 volts?
When the peak voltage is 311, the RMS voltage is 220. (311 * square root (2))
If a sine wave has a peak value of 220 volts what is the route means square value?
If the Peak to neutral voltage is 220 volts, the root mean square voltage is 155.6 volts (sqrt(220)).
What is the instantaneous voltage at 180 degrees for peak voltage of 150 volts?
Zero. If voltage starts at zero at zero degrees, it rises to peak voltage at 90 degrees. Voltage then reaches zero at 180 degrees and heads for negative peak voltage at 270 degrees and then back to zero at 360 degrees.
What is the effective value of 200 volts peak-to-peak?
200 volts peak-to-peak is 100 volts peak, which is 70.7 volts rms (standing for root-mean-square) also called "effective". This 70.7 volts is the DC voltage with the same heating power as the peak-to-peak. The relationship is: rms (aka RMS) equals peak-to-peak divided by 2, then divided again by square-root of 2 (1.414). The division by 2 gets us from peak-to-peak to just peak. The next division takes us to rms. If you get an AC voltrage with no description, for exmple 120 volts AC, it is RMS (effective). The USA AC standard supply voltage is 120 (also called 117) volts RMS. The USA peak is 117 x 1.414 (square root of 2) = 165 volts peak, = 330 volts peak-to-peak.
How do you convert peak voltage to peak-peak voltage?
Simply multiply the peak voltage to 2 and you will get the peak to peak voltage.
Convert rms to peak to peak power?
P-P voltage = RMS voltage * 2 * sqrt (2)Here's an example: house voltage is 120VRMS, which is actually ~169 volts peak - neutral. double this will give peak to peak value.
What is the peak value of the input to a half wave rectifier if the half wave rectifier is 10V?
In this case, the peak voltage, which is half the peak to peak voltage, is 100 volts. Additionally, the half-wave rectifier will only provide an output for half the input cycle. In the case of a full wave rectifier, the RMS output voltage would be about 0.707 times the value of the peak voltage (100 volts), which would be about 70.7 volts. But with the output operating only half the time (because of the half wave rectification), the average output voltage will be half the 70.7 volts, or about 35.35 volts RMS.
How to calculate the peak-to-peak value of a signal?
A: AC or our line voltage is sinusoidal in nature it goes up to a positive peak returns to zero and proceed to the negative peak. 120V AC is actually swinging from peak to peak. It is 120 volts but the peak is the 120 v times 1.41 or 169.2 volts and since it also go negative then the peak to peak 120 volts times 2.82 or 338.40 volts or twice the peak voltage
If each division on the y axis is worth 4 volts then what is the peak voltage?
I assume you are asked to find peak voltage on a graph. If so its simply the number of divisions times four volts for the highest point on the graph.
