RMS stands for "Root of the Means Squared", and is a mathematical method of defining the "operating" voltage of a sine wave power source.
Typical home lighting and outlet voltage presently is 120 VAC (volts alternating current), 60 Hz. (Hertz, formerly referred to as "cycles per second".)
But the PEAK voltage is the absolute maximum voltage at the "peak" of each sine wave of voltage. Mathematically, the "Peak" voltage is 1.414 (which is the square root of the number 2) times the RMS voltage, and conversely, the RMS voltage is 0.707 times the PEAK voltage.
Average Current = 0.636 * (Peak Current)so Peak Current = (Average Current)/0.636RMSCurrent = 0.707 * (Peak Current)so Peak Current = (RMS Current)/0.707Because both equations are in terms of Peak Current, we can set them equal to each other.(Average Current)/0.636 = (RMS Current)/0.707(42.5)/0.636 = (RMS Current)/0.707thenRMS Current = (0.707)(42.5)/0.636 = 47.24 ampsAnother AnswerSince the average value of a single sine wave is zero, you cannot calculate its r.m.s. value!
For sine waves:To calculate the RMS value of a sine wave, multiply the peak value by 0.707. The peak value is, of course, one half the peak-to-peak value. To go the other way, reverse the order of operations. That is, if you're starting with an RMS value, divide by 0.707 and then multiply by two to get the p-p value. Another way to convert from RMS to p-p is to multiply the RMS value by two square roots of two: RMS x 2 x SQR(2).Or more simply, to convert from RMS to peak to peak voltage:(RMS x 1.414) x 2=P-PFor example:120vac x 1.414= 170vac169.68vac x 2 = 339.36vac P-PWhere there is a significant reactive component in the characteristic of the cabling or load, we must also consider the effects of the X/R ratio. The real vs imaginary components of the impedance:V(peak) = V(rms) * sqrt(2) * (1+ e(exp -pi/(X/R)))where "exp" is the exponent to which the value of e is raised.Reading the power of e above in English:"e to the power of (minus pi divided by the X/R ratio)".Take careful note of the top line of the first answer "For sine waves". More specifically the formula applies only to a signal which is a pure sine wave (a single frequency, no harmonics or other frequencies). As soon as you combine two or more sine wave signals of different frequencies, the ratio of peak voltage to RMS voltage depends strongly on the phases of the component signals. Too complicated to answer here, in full explanation.Vrms = (Vp-p / 2 )/ sq.root (2) = Vp-p / 2.828 for sinusoidal waves..*Note: If the signal or the waveform is not sinusoidal you'll have to derive from basic steps with a sound knowledge about integrations.RMS = root mean square = square root (mean(square values of voltages))
RMS means root mean square and watts means power. What a difference! Scroll down to related links and look for a neat pressure converter at"Root Mean Square" und knowlege about "Watt" Watts root mean square is the effective value of alternating current electrical power compared to direct current power. Scroll down to related links and look for "Why there is no such thing as 'RMS watts' or 'watts RMS' and never has been". RMS watts is meaningless, but we use that term as "an extreme shorthand" for power in watts calculated from measuring the RMS voltage.
RMS and peak voltage for a square waveform are the same. There is a small caveat, and that is that you'd have to have a "perfect" square wave with a rise time of zero. Let's have a look. If we have a perfect square wave, it has a positive peak and a negative peak (naturally). And if the transition from one peak to the other can be made in zero time, then the voltage of the waveform will always be at the positive or the negative peak. That means it will always be at its maximum, and the effective value (which is what RMS or root mean square is - it's the DC equivalent or the "area under the curve of the waveform") will be exactly what the peak value is. It's a slam dunk. If we have a (perfect) square wave of 100 volts peak, it will always be at positive or negative 100 volts. As RMS is the DC equivalent, or is the "heating value for a purely resistive load" on the voltage source, the voltage will always be 100 volts (either + or -), and the resistive load will always be driven by 100 volts. Piece of cake.
Peak values times 0.707 gives the RMS value. This question cannot be answered without knowing the waveform of the voltage. If it is continuous direct current rms value is 100V. If it is a sine wave (like house current), the rms value is 100/ (sq. root(2)) or 70.7V approx. For a regular series of square pulses, it is 100V times the mark/(mark+space) ratio. Any other waveform, you need to calculate the root mean square value of the function. ( Square, integrate and take square root over one complete period.) If all the above fail, measure the heating effect in a 40K resistor. It will be 0.25 Watt or less - calculate from the result.
Its 0.7 times peak-0 voltage, 106 mv RMS.
rms. dat means Vp-p will be 325V.
The peak of a waveform that is purely sinusoidal (no DC offset) will be RMS * sqrt(2). This is the peak to neutral value. If you are looking for peak to peak, multiply by 2.
You can work this out yourself. For a sinusoidal waveform the rms value is 0.707 times the peak value. As you quote a peak-to-peak value, this must be halved, first. Incidentally, the symbol for volt is 'V', not 'v'.
When you say holdhold supply of 230volts, you are referring to the RMS value, not the peak value.
In an AC circuit the voltage and current are n the form of a sine wave that goes between a maximum and minimum value 60 times a second. Measuring the difference between these values is a peak-to-peak measurement. Root Mean Square (RMS) computes an average (mean). To convert RMS to peak, multiply the RMS figure by 1.41. 1.41 is an approximation of the value of the square root of 2.
RMS is the root mean square value.(in alternating current only)
Assuming "quoted value" to be RMS value, or average, [what you would see on a meter], the peak would be that value times 1.414. Going backward, peak times .707 is RMS.
A square wave has the highest RMS value. RMS value is simply root-mean-square, and since the square wave spends all of its time at one or the other peak value, then the RMS value is simply the peak value. If you want to quantify the RMS value of other waveforms, then you need to take the RMS of a series of equally spaced samples. You can use calculus to do this, or, for certain waveforms, you can use Cartwright, Kenneth V. 2007. In summary, the RMS value of a square wave of peak value a is a; the RMS value of a sine wave of peak value a is a divided by square root of 2; and the RMS value of a sawtooth wave of peak value a is a divided by cube root of 3; so, in order of decreasing RMS value, you have the square wave, the sine wave, and the sawtooth wave. For more information, please see the Related Link below.
To convert DC values to AC values if you are wanting RMS values they are the same. 100V DC and 100V AC (RMS) are the same "value". If you want to know the Peak-To-Peak AC value you would multiply the RMS value by 1.414. So 100V AC RMS equals 141.4 V Peak to Peak.
Peak voltage will be 1.414 times the RMS. Peak to Peak voltage, assuming no DC offset, will be 2 x 1.414 x the RMS value.
It is the highest value of the amplitude, called the peak value. Scroll down to related links and look at "RMS voltage, peak voltage and peak-to-peak voltage". Look at the figure in the middle below the headline "RMS voltage, peak voltage and peak-to-peak voltage".