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What is the instantaneous voltage of a sine wave at 25 degrees if its peak voltage is 30 V?
12.68V 3o * sin25 = 12.67854785
What is the effective voltage for a peak voltage of 311 volts?
When the peak voltage is 311, the RMS voltage is 220. (311 * square root (2))
Convert rms to peak to peak power?
P-P voltage = RMS voltage * 2 * sqrt (2)Here's an example: house voltage is 120VRMS, which is actually ~169 volts peak - neutral. double this will give peak to peak value.
How do you convert peak voltage to peak-peak voltage?
Simply multiply the peak voltage to 2 and you will get the peak to peak voltage.
What is peak to peak voltage?
Conversions of RMS voltage, peak voltage and peak-to-peak voltage. That are the used voltages. The expression "average" voltage is used for RMS voltage.Scroll down to related links and seach for "RMS voltage, peak voltage and peak-to-peak voltage".Answer'Average' is not the same as 'root mean square'. As the average value of a sinusoidal voltage is zero, you cannot convert it to a peak-to-peak value.
If the peak voltage of a sine wave is 100 volts then the instantaneous voltage at 150 and deg is volts?
To find the instantaneous voltage of a sine wave at a given angle, you can use the formula ( V(t) = V_{peak} \cdot \sin(\theta) ). For a peak voltage of 100 volts and at 150 degrees, convert 150 degrees to radians if necessary or use the sine function directly. The sine of 150 degrees is 0.5, so the instantaneous voltage is ( 100 \cdot \sin(150^\circ) = 100 \cdot 0.5 = 50 ) volts.
What is the instantaneous voltage of a sine wave at 25 degrees if its peak voltage is 30 V?
12.68V 3o * sin25 = 12.67854785
What is the instantaneous voltage of 90 degrees?
The instantaneous voltage at 90 degrees in a sinusoidal waveform is at its peak value, as this angle corresponds to the maximum point of the sine function. Mathematically, if the voltage is represented as ( V(t) = V_{\text{max}} \sin(\omega t + \phi) ), at 90 degrees (or ( \frac{\pi}{2} ) radians), the voltage is ( V(t) = V_{\text{max}} ). Thus, the instantaneous voltage is equal to the maximum amplitude of the waveform.
What is the peak to peak voltage for the AC line voltage in normal outlets of your house?
Peak - neutral for 120 volts RMS is 169 volts, or 120 * sqrt(2) Peak to peak will be 2 x this value, or 339 volts.
Utility voltage is 115 volts at a frequency of 60 Hz what is the peak to peak?
A: Take 115 volts and multiply by 2.82. The frequency does not matter but he voltage does
What is the effective voltage for a peak voltage of 311 volts?
When the peak voltage is 311, the RMS voltage is 220. (311 * square root (2))
If a sine wave has a peak value of 220 volts what is the route means square value?
If the Peak to neutral voltage is 220 volts, the root mean square voltage is 155.6 volts (sqrt(220)).
Ac transformer has 6.3 volt secondary output What is the peak to peak voltage available to the secondary terminals of this transformer?
To find the peak-to-peak voltage from the secondary output of an AC transformer, you start with the RMS voltage, which is 6.3 volts in this case. The peak voltage (Vp) can be calculated using the formula ( Vp = V_{RMS} \times \sqrt{2} ). Thus, ( Vp = 6.3 \times \sqrt{2} \approx 8.9 ) volts. The peak-to-peak voltage (Vpp) is then twice the peak voltage, so ( Vpp \approx 2 \times 8.9 \approx 17.8 ) volts.
What is the effective value of 200 volts peak-to-peak?
200 volts peak-to-peak is 100 volts peak, which is 70.7 volts rms (standing for root-mean-square) also called "effective". This 70.7 volts is the DC voltage with the same heating power as the peak-to-peak. The relationship is: rms (aka RMS) equals peak-to-peak divided by 2, then divided again by square-root of 2 (1.414). The division by 2 gets us from peak-to-peak to just peak. The next division takes us to rms. If you get an AC voltrage with no description, for exmple 120 volts AC, it is RMS (effective). The USA AC standard supply voltage is 120 (also called 117) volts RMS. The USA peak is 117 x 1.414 (square root of 2) = 165 volts peak, = 330 volts peak-to-peak.
What is the peak value of the input to a half wave rectifier if the half wave rectifier is 10V?
In this case, the peak voltage, which is half the peak to peak voltage, is 100 volts. Additionally, the half-wave rectifier will only provide an output for half the input cycle. In the case of a full wave rectifier, the RMS output voltage would be about 0.707 times the value of the peak voltage (100 volts), which would be about 70.7 volts. But with the output operating only half the time (because of the half wave rectification), the average output voltage will be half the 70.7 volts, or about 35.35 volts RMS.
Convert rms to peak to peak power?
P-P voltage = RMS voltage * 2 * sqrt (2)Here's an example: house voltage is 120VRMS, which is actually ~169 volts peak - neutral. double this will give peak to peak value.
How do you convert peak voltage to peak-peak voltage?
Simply multiply the peak voltage to 2 and you will get the peak to peak voltage.
