Blue light will eject electrons from a photosensitive surface because blue light has a high frequency. The high photon frequency of the blue light means it has more energy because the frequency is directly linked to the energy of the photons. Red light would not eject electrons because it has a low frequency.
Using the formula:
photon energy (E) = Planck constant (h) * frequency (Æ’) Blue has a higher frequency than red. Since h is constant, E increases as Æ’ increases.
Using the formula:
photon energy (E) = Planck constant (h) * speed of light (c) / wavelength (λ)
Blue has a shorter wavelength than red. Since h and c are considered constant, E increases as λ decreases.
Blue light will eject electrons from a photosensitive surface because blue light has a high frequency. The high photon frequency of the blue light means it has more energy because the frequency is directly linked to the energy of the photons. Red light would not eject electrons because it has a low frequency.
In order to eject an electron from an atom, sufficient energy is required. Photons of blue light are more energetic than photons of red light.
(It's possible that two photons of red light could collectively supply enough energy to eject an electron, but this kind of concerted mechanism would be quite rare.)
The principle of the matter goes like this:
-- It takes a certain amount of energy for an electron to break free of the atom
to which it's bound.
-- Electrons can't save up a little bit of energy that comes in now and some more
energy that arrives later until it has enough to make the break. It has to get the
amount of energy it needs all at once, in a single shot.
-- A photon of red light doesn't have enough energy to enable the electron to
escape. It doesn't matter how bright the red light is. That just means there are
more photons. But each photon still has the same energy, and the electron can't
put together the energy from two of them. It needs to get it all in one gulp.
-- A photon of blue light has more energy than a photon of red light. So it
doesn't matter how dim the blue light is. That just means there are fewer
photons. But each and every one of them has enough energy to enable the
electron to break free of its atom.
This was the work that got Albert Einstein his first Nobel Prize.
Blue light has higher energy than red light., E=hf. There is a minimum energy necessary to emit an electron from metal and red light is below that minimum.
i have the same question on my test haha for me, the answers are: a) The number of electrons ejected per second b) the maximum kinetic energy of the ejected electrons c) the threshold frequency of the ejected electrons d) the time lag between the absorption of blue light and the start of emission of the electrons e) none of these A the number of electrons ejected per second,,,,, correct answer
There is the photoelectric effect, which is the process that emitts electrons from a metals surface when light of a certain frequency shines on the surface. In the metal, the nuclei are surrounded by electrons, so when the incoming electrons strike the surface, they pull apart from the electrons of the metal because of how like charges detract from each other.
False. Black body radiation refers to the emission of light from an object that absorbs all incident radiation. While metals can emit light, the term "black body radiation" specifically refers to the emission from an idealized object, called a black body, which is not typically applicable to metal surfaces.
Photo relates to light. Of course light is electromagnetic wave. Electric relates to electron movement. So by making electromagnetic waves such gamma ray, X-ray, UV rays and even visible light we can eject electrons right from the surface of certain substances. This is termed as photo electric effect or emission.
Photoelectric effect.===================================== This phenomenon was discovered by Albert Einstein, for which he received the Nobel Prize for Physics. The solar cells that we use today is a direct application of the photoelectric effect, as the special metal absorbs Sun's photons and gives off electron (and the flow of electrons generates an electric current).
This is an interaction between photons and the surface of the metal.
The process in which an electron emit from metal surface into surrounding is known as electrons emission
reflection??
Light can cause electrons to be released from the surface of a metal. <<<<Apex>>>>
the external energy given to electrons,thier kinetic energy increases.thus electrons move from metal surface
* emisssion of electron from the surface of the metal when light of suitable frequency falls-photoelectric emission. * emision of electron from the metal by quantum tunnling of electron.
The electrons in the electron sea absorb and re-emit the light.
Visible light of a different frequency is a different color. Visible light of a higher frequency is closer to the violet end of the spectrum. If the frequency of a light source were increased, then the wavelength of its emission would decrease, because the product of (frequency) x (wavelength) is always the same number for all light in the same medium.
i have the same question on my test haha for me, the answers are: a) The number of electrons ejected per second b) the maximum kinetic energy of the ejected electrons c) the threshold frequency of the ejected electrons d) the time lag between the absorption of blue light and the start of emission of the electrons e) none of these A the number of electrons ejected per second,,,,, correct answer
no time lag.................
shock
Emissivity of a surface is defined as its effectiveness in emitting thermal radiation. The term photo emissivity is likely used to narrow the focus to emitting visible light.